所以我有一些 shared_mutex 并完成了这个:
boost::upgrade_lock<boost::shared_mutex> lock(f->mutex);
boost::upgrade_to_unique_lock<boost::shared_mutex> uniqueLock(lock);
现在我想“解锁”或至少将其降级为:
boost::shared_lock<boost::shared_mutex> lock_r(f->mutex);
如何做这样的事情?可能吗?
最佳答案
如果您让 upgrade_to_unique_lock
超出范围,它将自动降级回升级所有权。
例如
void foo() {
boost::upgrade_lock<boost::shared_mutex> lock(f->mutex);
// Do shared operations, as mutex is held upgradeable
// ...
if(need_to_get_unique)
{
boost::upgrade_to_unique_lock<boost::shared_mutex> uniqueLock(lock);
// Do exclusive operations, as mutex is held uniquely
// ...
// At end of scope unique is released back to upgradeable
}
// Only shared operations here, as it's only held upgradeable
// ...
// At end of scope mutex is completely released
}
编辑:另一件事。如果给定的函数只需要独占锁,您可以使用 boost::unique_lock
并进行唯一锁定,而无需同时使用 upgrade
和 upgrade_to_unique
锁.
关于c++ - 如何解锁 boost::upgrade_to_unique_lock(由 boost::shared_mutex 制成)?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/7704870/