我正在尝试在 VC++ 2005 中编译以下基于模板的代码。
#include <iostream>
using namespace std;
/*
* T is a template which maps an integer to a specific type.
* The mapping happens through partial template specialization.
* In the following T<1> is mapped to char, T<2> is mapped to long
* and T<3> is mapped to float using partial template specializations
*/
template <int x>
struct T
{
public:
};
template<>
struct T<1>
{
public:
typedef char xType;
};
template<>
struct T<2>
{
public:
typedef long xType;
};
template<>
struct T<3>
{
public:
typedef float xType;
};
// We can easily access the specific xType for a specific T<N>
typedef T<3>::xType x3Type;
/*!
* In the following we are attempting to use T<N> inside another
* template class T2<R>
*/
template<int r>
struct T2
{
//We can map T<r> to some other type T3
typedef T<r> T3;
// The following line fails
typedef T3::xType xType;
};
int main()
{
T<1>::xType a1;
cout << typeid(a1).name() << endl;
T<2>::xType a2;
cout << typeid(a2).name() << endl;
T<3>::xType a3;
cout << typeid(a3).name() << endl;
return 0;
}
代码中有一行无法编译:
typedef T3::xType xType;
如果我删除这一行,编译会正常进行,结果是:
char
long
float
如果我保留这一行,则会观察到编译错误。
main.cpp(53) : warning C4346: 'T<x>::xType' : dependent name is not a type
prefix with 'typename' to indicate a type
main.cpp(54) : see reference to class template instantiation 'T2<r>' being compiled
main.cpp(53) : error C2146: syntax error : missing ';' before identifier 'xType'
main.cpp(53) : error C4430: missing type specifier - int assumed. Note: C++ does not support default-int
我无法弄清楚如何确保 T::xType 可以被视为 T2 模板中的一种类型。非常感谢任何帮助。
最佳答案
自 T3
在你的模板类中取决于模板参数,编译器无法确定是什么 T3::xType
将引用(这可能取决于每个实例化中的实际类型 r
T2<r>
)。
告诉编译器 T3::xType
将是一种类型,您需要添加 typename
关键词:
typedef typename T3::xType xType;
关于c++ - 在特定情况下使用 C++ 模板将整数映射到类型失败,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3037846/