我们目前的情况是我们的代码在我们的 Java 层中使用枚举,它使用如下构造函数存储一个 id 和一个“显示值”:
public enum Status implements EnumIdentity {
Active(1, "Active"),
AwaitingReview(2, "Awaiting Review"),
Closed(3, "Closed"),
Complete(4, "Complete"),
Draft(5, "Draft"),
InProcess(6, "In Process"),
InReview(7, "In Review"),
NotStarted(8, "Not Started"),
PendingResolution(9, "Pending Resolution"),
Rejected(10, "Rejected");
private int id;
private String displayValue;
PlanStatus(final int id, String displayValue) {
this.id = id;
this.displayValue = displayValue;
}
/** {@inheritDoc} */
@Override
public int id() {
return id;
}
public String getDisplayValue() {
return displayValue;
}
}
我们希望 typescript 中的某些东西与此匹配,以允许以有意义的方式显示状态以执行逻辑并在前端向用户显示值。 这可能吗?有没有更好的方法来处理这个问题?我们希望避免使用诸如 status.id() = 1 或 status.name() = 'Active' 这样的逻辑来插入枚举。
谢谢
最佳答案
Typescript 不支持扩展枚举,例如在 java 中。您可以使用类实现类似的效果:
interface EnumIdentity { }
class Status implements EnumIdentity {
private static AllValues: { [name: string] : Status } = {};
static readonly Active = new Status(1, "Active");
static readonly AwaitingReview = new Status(2, "Awaiting Review");
static readonly Closed = new Status(3, "Closed");
static readonly Complete = new Status(4, "Complete");
static readonly Draft = new Status(5, "Draft");
static readonly InProcess = new Status(6, "In Process");
static readonly InReview = new Status(7, "In Review");
static readonly NotStarted = new Status(8, "Not Started");
static readonly PendingResolution = new Status(9, "Pending Resolution");
static readonly Rejected = new Status(10, "Rejected");
private constructor(public readonly id: number, public readonly displayValue: string) {
Status.AllValues[displayValue] = this;
}
public static parseEnum(data: string) : Status{
return Status.AllValues[data];
}
}
关于java - typescript 枚举的构造函数?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47713743/