我正在为家庭作业编写此代码(刚开始使用 C++,所以请放轻松)。我们今天刚刚开始了 while、do-while 和 for 循环。该程序运行良好,只是如果您在程序要求整数时输入一个字母,它将无限循环。到底是怎么回事? (代码如下) ***编辑:为了澄清,循环的部分是:“您输入的数字是负数。请输入正数以继续。”但是用户没有机会输入另一个号码。它只是不断打印这个。
#include <iostream>
using namespace std;
int main ( )
{
//define variables
int num1, num2, total;
char answer1;
do
{
//user enters a number
cout << "\nPlease enter a positive number and press Enter: \n";
cin >> num1;
//check that the given num1 value is positive
while (num1 < 0)
{
cout << "The number you entered is negative.\nPlease enter a positive number to continue.\n";
cin >> num1;
}
cout << endl;
//add the sum of 1 through num1 value
num2 = 1;
total = 0;
while (num1 >= num2)
{
total = total + num2;
num2 ++;
}
//tell the user the sum
cout << "The total of all the integers\nfrom 1 to " << num1 << " is: \n";
cout << total;
//ask if the user wants to try again
cout << "\n\nWould you like to try again with a new number?\nEnter y for yes or n for no.\n";
cin >> answer1;
} while (answer1 == 'y');
cout << endl;
return 0;
}
最佳答案
basic_istream
就是这样工作的。在您的情况下,当 cin >> num1
输入错误时 - failbit
已设置且 cin
未清除。所以下次它会是同样的错误输入。要正确处理此问题,您可以添加检查输入是否正确,并在输入错误的情况下清除&ignore cin
。例如:
#include<limits>
//user enters a number
cout << "\nPlease enter a positive number and press Enter: \n";
do {
while(!(cin >> num1)) {
cout << "Incorrect input. Please try again.\n";
cin.clear();
cin.ignore(numeric_limits<streamsize>::max(), '\n');
}
if(num1 < 0) cout << "The number you entered is negative. Please enter a positive number to continue.\n";
} while(num1 < 0);
关于c++ - 如果我输入字母而不是数字,为什么会出现无限循环?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19521320/