我正在从 foursquare 获取一份 field 列表,我需要我获得的每个 field 的名称、地址和城市。这里我的问题是,如果地址或城市为空,它会给出错误并显示“JSON 异常:地址无值”。我尝试了不同的方法来修复它,但无法解决问题。我希望你可以帮助我。谢谢。
JSONObject b = venues.getJSONObject(i);
JSONObject location = b.getJSONObject("location");
String name = "";
String address = "";
String city = "";
if ("".equals(b.get("name"))) {
// Toast.makeText(Activity2.this,"Name of Place: " +name+ " Location: "+country, Toast.LENGTH_SHORT).show();
name = "No place ";
} else {
name = b.getString("name");
}
if ("".equals(location.getString("address"))) {
address = "No address";
} else {
address = location.getString("address");
}
if ("".equals(location.getString("city"))) {
city = "No city";
} else {
city = location.getString("city");
}
name = "Name of the place: " + name;
// + " Address: "+ address + " City: " + city;
list.add(name);
最佳答案
您可能需要在调用 getString 之前调用 has() 方法以避免异常。但还有一种更简单的方法 - 只需使用 optString而不是 getString,如果该值不存在,它将返回“后备”字符串。
String name = location.optString("name", "No Place");
String address = location.optString("address", "No Address");
String city = location.optString("city", "No City");
关于java - 具有空字段的 JSON 对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22735090/