我收到以下错误:
java.lang.StringIndexOutOfBoundsException: length=13243; regionStart=32; regionLength=-39
at java.lang.String.startEndAndLength(String.java:593)
at java.lang.String.substring(String.java:1474)
at com.dict.XMLParser.getResultFromXML(XMLParser.java:63)
at com.dict.InternetDictProvider.searchWord(InternetDictProvider.java:29)
at com.dict.SearchDict$SearchOnline.doInBackground(SearchDict.java:130)
at com.dict.SearchDict$SearchOnline.doInBackground(SearchDict.java:1)
at android.os.AsyncTask$2.call(AsyncTask.java:264)
at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:305)
at java.util.concurrent.FutureTask.run(FutureTask.java:137)
at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:208)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1076)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:569)
at java.lang.Thread.run(Thread.java:856)
在以下代码中，通常在解析作为 HttpGet 的 HttpResponse 给出的 XML 页面后获取结果:
retry:
{
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet httpGet = new HttpGet("http://oxforddictionaries.com/definition/"+query+"?q="+query);
HttpResponse httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
String meanings=parser.getResultFromXML(StringUtils.inputStreamToString(httpEntity.getContent()));
if(meanings==null && firstRetry)
{
firstRetry=false;
query = query.substring(0, 1).toUpperCase() + query.substring(1);
break retry;
}
else if(meanings==null && !firstRetry)
return query;
result = query + ":" + meanings;
}
最佳答案
query = query.substring(0, 1).toUpperCase() + query.substring(1);
我认为这个语句会创建异常，所以使用 if(null!=query&&query.length()!=0){query=...}
如果您对字符串进行子串在您的情况下长度超过 1
关于android - Android 中的 StringIndexOutOfBoundsException，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/9781802/