java - 从 ArrayOfByte 中逐字节提取

Question

我有一个像这样的 ArrayOfByte:

byte[] arrayOfByte = new byte[1024]

它随机包含 1,2,3,4 的数组..

假设里面有大约100Byte的数据，

我的问题是如何从中提取字节数据: 如果我使用 Log.d(TAG, "arrayOfByte :"+arrayOfByte); 它将显示 arrayOfByte :[B@2b052c60

现在我想单独提取每个字节并显示:1,1,2,1,3,3,3,2,2,1,4,4,4,2,3,3,3 ... 像这样

更新: 谢谢Sumit Singh，它成功了..

现在假设我们显示:[1,1,1,2,3,2,2,2,1,1,1,0,0,0,0,0,0,0]

问题1:如何将这些值放入某些int[]系列

问题2:我可以从中删除一些起始元素并将其设为[2,2,1,1,1,0,0,0,0,0,0,0 ]

Answer 1

您可以使用Arrays.toString(byte[] a) :

Returns a string representation of the contents of the specified array. The string representation consists of a list of the array's elements, enclosed in square brackets ("[]"). Adjacent elements are separated by the characters ", " (a comma followed by a space). Elements are converted to strings as by String.valueOf(byte). Returns "null" if a is null.

Arrays.toString(arrayOfByte) 

它将返回字节数组的字符串表示形式，例如 1,1,2,1,3,3,3,2,2,1,4,4,4,2,3,3,3 所以

Log.d(TAG, "arrayOfByte :"+ Arrays.toString(arrayOfByte));

更新了下一个问题

答案1:

• 有很多方法可以做到这一点，最简单的是迭代每个字节数组元素并将基元从 char 扩大到 int:JLS 5.1.2 Widening Primitive Conversion

• 您可以使用ByteBuffer它是 NIO 的一部分，如下所示:

  int[] intArray = ByteBuffer.wrap(arrayOfByte).asIntBuffer().array()

答案2:

对于这个问题也有很多方法，我建议使用 Arrays.copyOfRange 。它将返回具有给定范围的新数组。

Copies the specified range of the specified array into a new array. The initial index of the range (from) must lie between zero and original.length, inclusive. The value at original[from] is placed into the initial element of the copy (unless from == original.length or from == to). Values from subsequent elements in the original array are placed into subsequent elements in the copy. The final index of the range (to), which must be greater than or equal to from, may be greater than original.length, in which case (byte)0 is placed in all elements of the copy whose index is greater than or equal to original.length - from. The length of the returned array will be to - from.

byte[] newByteArray = Arrays.copyOfRange(arrayOfByte, startIndex, endIndex);