我正在尝试从我的手机获取联系人,但我想将数据发布到 php 服务以存储在数据库中。检索后,我创建了一个包含名称值对的数组,代码段
public void getContacts() throws IOException, JSONException {
List<String> phnnumbers = new ArrayList<String>();
List<String> names = new ArrayList<String>();
ContentResolver cr = getContentResolver();
Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,
null, null, null, null);
if (cur.getCount() > 0) {
while (cur.moveToNext()) {
String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
String name = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
if (Integer.parseInt(cur.getString(cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
System.out.println("name : " + name + ", ID : " + id);
names.add(name);
// get the phone number
Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?",
new String[]{id}, null);
while (pCur.moveToNext()) {
String phone = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
System.out.println("phone" + phone);
phnnumbers.add(phone);
}
}
}
Log.d("NAMES",name.toString());
// registerContacts(this,URL,names,phnnumbers);
}
}
输出是这样的
[name[]="Chacha Kori, phone[]="+123456987", name[]="Gabuli Somi", [phone[]="+123456789",name[]="Geto Somi", phone[]="+123456789",
我如何格式化它以便我可以将它存储在数据库中。我的 php 方面
function SynchContacts() {
$phone = $this->input->post('phone');
$name = $this->input->post('name');
for ($i = 0; $i < count($phone); $i++) {
$data = array(
'name' => $name[$i],
'phone' => $phone[$i]
);
$this->saveData('phonebook', $data);
}
}
有什么建议吗?
最佳答案
我的建议是不要使用 NameValuePair,因为在 Lollipop 版本之上,NameValuePair 已被弃用,因此最好使用 Arraylist。
public void getContacts() {
List<String> phnnumbers = new ArrayList<String>();
List<String> names = new ArrayList<String>();
ContentResolver cr = getContentResolver();
Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,
null, null, null, null);
if (cur.getCount() > 0) {
while (cur.moveToNext()) {
String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
String name = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
if (Integer.parseInt(cur.getString(cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
System.out.println("name : " + name + ", ID : " + id);
names.add(name);
// get the phone number
Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?",
new String[]{id}, null);
while (pCur.moveToNext()) {
String phone = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
System.out.println("phone" + phone);
phnnumbers.add(phone);
}
pCur.close();
}
}
}
}
你的 Json 调用部分应该如下所示,
private static JSONObject post(String sUrl, String body) {
Log.d("post", sUrl);
Log.d("post-body", sanitizeJSONBody(body));
HttpURLConnection connection = null;
String authentication = "example" + ":" + "exam123ple";
String encodedAuthentication = Base64
.encodeToString(authentication.getBytes(), Base64.NO_WRAP);
try {
URL url = new URL(sUrl);
connection = (HttpURLConnection) url.openConnection();
connection.setDoOutput(true);
connection.setDoInput(true);
connection.setRequestMethod("POST");
connection.setRequestProperty("Content-Type", "application/json");
connection.setRequestProperty("Accept", "application/json");
connection.setRequestProperty("Authorization",
"Basic " + encodedAuthentication);
connection.setRequestProperty("Accept-Charset", "utf-8,*");
OutputStreamWriter streamWriter = new OutputStreamWriter(
connection.getOutputStream());
streamWriter.write(body);
streamWriter.flush();
StringBuilder stringBuilder = new StringBuilder();
if (connection.getResponseCode() == HttpURLConnection.HTTP_OK) {
InputStreamReader streamReader = new InputStreamReader(
connection.getInputStream());
BufferedReader bufferedReader = new BufferedReader(
streamReader);
String response = null;
while ((response = bufferedReader.readLine()) != null) {
stringBuilder.append(response + "\n");
}
bufferedReader.close();
Log.d("Post-Response",
sanitizeJSONBody(stringBuilder.toString()));
return new JSONObject(stringBuilder.toString());
} else {
Log.d("Post-Error", connection.getResponseMessage());
return null;
}
} catch (Exception exception) {
Log.e("Post-Exception", exception.toString());
return null;
} finally {
if (connection != null) {
connection.disconnect();
}
}
}
联系人数据需要通过以下方式发送:
public static JSONObject registerTask(Context ctx, String sUrl, List<String> names, List<String> phoneNums) throws JSONException, IOException {
JSONObject request = new JSONObject();
request.putOpt("names", names);
request.putOpt("phoneNums", phoneNums);
sUrl = sUrl + "yourapiname";
return post(sUrl, request.toString());
}
private static String sanitizeJSONBody(String body) {
if (body.contains("password")) {
body = body.replaceAll("\"password\":\"[^\"]+\"",
"\"password\":******");
}
if (body.contains("newPassword")) {
body = body.replaceAll("\"newPassword\":\"[^\"]+\"",
"\"newPassword\":******");
}
return body;
}
您的 PHP 代码将如下所示,
$inputJSON = file_get_contents('php://input');
$input = json_decode($inputJSON, TRUE);
$nameArray = array($input['names']);
$phoneNumArray = array($input['phoneNums']);
for($i=0;i<count($nameArray);$i++){
$data = array(
'name' => $nameArray[$i],
'phone' => $phoneNumArray[$i],
);
$this->saveData('phonebook', $data);
}
关于java - 将 JSONArray 发布到 php,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41055056/