java - MyWebViewClient 类型未定义方法 startActivity(Intent)

Question

我正在尝试使用 Android 教程构建一个应用程序，将 WebView 加载到我构建的移动网站。问题在于跟随教程 startActivity 函数未定义，Android 教程没有帮助。我已完成 Ctrl+Shift+O 以验证是否已加载所有正确的模块。

package com.mysite;

import android.content.Intent;
import android.net.Uri;
import android.webkit.WebView;
import android.webkit.WebViewClient;

public class MyWebViewClient extends WebViewClient {
    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        if (Uri.parse(url).getHost().equals("www.mysite.com")) {
            // This is my web site, so do not override; let my WebView load the page
            return false;
        }
        // Otherwise, the link is not for a page on my site, so launch another Activity that handles URLs
        Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
        startActivity(intent);
        return true;
    }
}

更新

好的，现在我的代码是这样的:

package com.myapp;

import android.app.Activity;
import android.content.Intent;
import android.net.Uri;
import android.os.Bundle;
import android.webkit.WebSettings;
import android.webkit.WebView;

public class MyApp extends Activity {
    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        //init webview
        WebView DCWebView = (WebView) findViewById(R.id.webview);
        WebSettings webViewSettings = DCWebView.getSettings();

        //when a link is clicked, use the WebView instead of opening a new browser
        DCWebView.setWebViewClient(new MyWebViewClient() {
            @Override
            public void launchExternalBrowser(String url) {
                Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
                startActivity(intent);
            }
        });

        //enable javascript
        webViewSettings.setJavaScriptEnabled(true);

    }
}

但我显示了 2 个错误:

Description Resource    Path    Location    Type
The type new MyWebViewClient(){} must implement the inherited abstract method MyWebViewClient.launchExternalBrowser()   DealClippings.java  /MyApp/src/com/myapp    line 21 Java Problem

The method launchExternalBrowser(String) of type new MyWebViewClient(){} must override or implement a supertype method  MyApp.java  /DealClippings/src/com/myapp    line 23 Java Problem

Answer 1

WebViewClient 确实没有startActivity 方法。您可以查看 docs .您必须向 Context(可能是您的 Activity)发出信号来执行这些代码行。有许多可能的方法，包括添加监听器或简单地调用抽象方法，您在 Activity 中设置 WebView 的 WebViewClient 时在此类的匿名实例中实现。

例如:

public abstract class MyWebViewClient extends WebViewClient {
    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        if (Uri.parse(url).getHost().equals("www.mysite.com")) {
            // This is my web site, so do not override; let my WebView load the page
            return false;
        }

        launchExternalBrowser(url);            
        return true;
    }

    public abstract void launchExternalBrowser(String url);
}

然后在您的 Activity 中:

WebViewClient client = new MyWebViewClient() {
    @Override
    public void launchExternalBrowser(String url) {
         Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
         startActivity(intent);
    }
};

虽然我不确定您为什么想要这种行为，但它应该或多或少起作用。