我需要通过电子邮件获取联系人信息(光标)。它们必须是不同的。如果他收到电子邮件,则每个联系人必须有一个条目。怎么做?我的目标是 2.0 附带的新联系人 API。
1)我尝试使用 CursorJoiner 来完成它,但是发生了一件奇怪的事情。这是我的代码:
MatrixCursor matCur = new MatrixCursor(
new String[]{
Contacts._ID,
Contacts.DISPLAY_NAME,
"photo_id",
"starred"
}
);
Cursor newContactCursor = managedQuery(
ContactsContract.Contacts.CONTENT_URI,
new String[]{
Contacts._ID,
Contacts.DISPLAY_NAME,
"photo_id",
"starred"
},
null,
null,
null//Contacts._ID
);
newContactCursor.moveToFirst();
Cursor emailCur = managedQuery(
ContactsContract.CommonDataKinds.Email.CONTENT_URI,
new String[] {
Email.CONTACT_ID,
Email.DATA1
},
null,
null,
Email.CONTACT_ID
);
emailCur.moveToFirst();
CursorJoiner joiner = new CursorJoiner(
newContactCursor,
new String[]{Contacts._ID},
emailCur,
new String[] {Email.CONTACT_ID}
);
for (CursorJoiner.Result joinerResult : joiner) {
switch (joinerResult) {
case LEFT:
// handle case where a row in cursorA is unique
//Log.i(TAG,"L|"+
//newContactCursor.getString(newContactCursor.getColumnIndex("_id")) );
break;
case RIGHT:
// handle case where a row in cursorB is unique
//Log.i(TAG,
//"R|"+
//emailCur.getString(emailCur.getColumnIndex("contact_id")) );
break;
case BOTH:
//Log.i(TAG,
//"L|"+
//newContactCursor.getString(newContactCursor.getColumnIndex("_id"))+
//"|R|"+
//emailCur.getString(emailCur.getColumnIndex("contact_id")) );
Log.i(TAG, newContactCursor.getString(newContactCursor.getColumnIndex("_id"))+"|"+
newContactCursor.getString(newContactCursor.getColumnIndex("display_name"))+"|"+
emailCur.getString(emailCur.getColumnIndex(Email.DATA1)));
String[] columnValues =
{newContactCursor.getString(newContactCursor.getColumnIndex("_id")),
newContactCursor.getString(newContactCursor.getColumnIndex("display_name")),
newContactCursor.getString(newContactCursor.getColumnIndex("photo_id")),
newContactCursor.getString(newContactCursor.getColumnIndex("starred"))
};
matCur.addRow(columnValues);
break;
}
}
现在我的问题是我得到这样的输出: 在此日志中它的 _id |显示名称 |电子邮件ID 由于隐私问题,我已经更换了它们
1|[contact name]|[email id]
4|[contact name]|[email id]
5|[contact name]|[email id]
6|[contact name]|[email id]
7|
8|
9|
90|
91|
92|
93|
94|
95|
96|
97|
98|
99|
但是你可以看到它直接从9跳到90然后都是9 9 9,这是什么?
2) 我们可以使用 distinct 关键字来做到这一点吗?是否可以使用像 ContactsContract 这样的联系提供者?
最佳答案
尝试使用这个 fragment : 在 ListView 中的同一行显示联系人姓名和电子邮件。
/**
* Populate the contact list based on account.
*/
private void populateContactList() {
// Build adapter with contact entries
Cursor cursorEmail = getContactsEmail();//get all emails
String[] fields = new String[] //fields of data to take
{ ContactsContract.Contacts._ID,
ContactsContract.Data.DISPLAY_NAME,
ContactsContract.CommonDataKinds.Email.DATA
};
SimpleCursorAdapter adapter =
new SimpleCursorAdapter(this, R.layout.contact_entry, cursorEmail ,
fields, new int[]
{R.id.UID,R.id.contactEntryText,R.id.contactEmail});
mContactList.setAdapter(adapter);
}
/**
* Obtains the contact list for the currently selected account.
*
* @return A cursor for for accessing the contact list.
*/
private Cursor getContactsEmail()
{
// Run query
Uri uri = ContactsContract.CommonDataKinds.Email.CONTENT_URI;
String[] projection = new String[] {
ContactsContract.Contacts._ID,
ContactsContract.Contacts.DISPLAY_NAME,
ContactsContract.CommonDataKinds.Email.DATA
};
String selection = ContactsContract.Contacts.IN_VISIBLE_GROUP +"='1'";
//showing only visible contacts
String[] selectionArgs = null;
String sortOrder = ContactsContract.Contacts.DISPLAY_NAME + " COLLATE LOCALIZED ASC";
return managedQuery(uri, projection, selection, selectionArgs, sortOrder);
}
关于android - 使用电子邮件 ID 获取联系人,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5258984/