我正在使用一个应用程序，我只需要从 mysql 服务器下载一对谷歌地图的坐标。我可以使用 php 和普通的 httpost 成功地做到这一点，但是当我这样做时我的应用程序卡住了几秒钟。
我读到您需要使 httppost 异步，以避免在服务器完成处理并发送结果之前卡住。
关键是我需要像普通 httpost 一样生成一个 json 数组。
例如，如果我有这个 httppost。
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://www.yoursite.com/script.php");
try {
// Add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("id", "12345"));
nameValuePairs.add(new BasicNameValuePair("stringdata", "AndDev is Cool!"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}
String result11 = null;
// convert response to string
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(is11, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
sb.append(reader.readLine() + "\n");
String line = "0";
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is11.close();
result11 = sb.toString();
} catch (Exception e) {
Log.e("log_tag", "Error converting result " + e.toString());
}
// parsing data
try {
JSONArray jArray1 = new JSONArray(result11);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
我怎样才能将其转换为异步发布，从而避免卡住？
最佳答案
有一个很好的类 AsyncTask 可以用来轻松地运行异步任务。如果您将代码嵌入到这样的子类中，您可能会得到这样的结果:
public class FetchTask extends AsyncTask<Void, Void, JSONArray> {
@Override
protected JSONArray doInBackground(Void... params) {
try {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://www.yoursite.com/script.php");
// Add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("id", "12345"));
nameValuePairs.add(new BasicNameValuePair("stringdata", "AndDev is Cool!"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
BufferedReader reader = new BufferedReader(new InputStreamReader(response.getEntity().getContent(), "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
sb.append(reader.readLine() + "\n");
String line = "0";
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
reader.close();
String result11 = sb.toString();
// parsing data
return new JSONArray(result11);
} catch (Exception e) {
e.printStackTrace();
return null;
}
}
@Override
protected void onPostExecute(JSONArray result) {
if (result != null) {
// do something
} else {
// error occured
}
}
}
您可以使用以下方式开始任务:
new FetchTask().execute();
其他资源:
关于android - 异步 HTTP post android，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/9954477/