android - 显示设置弹出窗口的位置？

Question

我必须显示弹出窗口。我已经做到了，但我无法设置此弹出窗口的位置。 我必须在 friend 标签下方设置弹出窗口。

.

代码:

_spinner = (Spinner) view.findViewById(R.id.group_spinner);
_groupAdaptor = new ArrayAdapter(getActivity(), 
                android.R.layout.simple_spinner_dropdown_item, _itemGroupList);
_spinner.setAdapter(_groupAdaptor);
_spinner.setOnItemSelectedListener(this);

然后点击我调用如下方法:

_spinner.performClick();

Answer 1

使用我的工作代码..

Rect r = locateView(v);    
final PopupWindow popup = new PopupWindow(getActivity());
            popup.setAnimationStyle(R.style.animation);
            popup.setContentView(layout);
            popup.setHeight(WindowManager.LayoutParams.WRAP_CONTENT);
            popup.setWidth(getActivity().getWindowManager().getDefaultDisplay().getWidth() / 2);
            popup.setFocusable(true);
            popup.setBackgroundDrawable(new BitmapDrawable());
            popup.showAtLocation(layout, Gravity.TOP | Gravity.LEFT, r.right, r.bottom);


public static Rect locateView(View v) {
        int[] loc_int = new int[2];
        if (v == null)
            return null;
        try {
            v.getLocationOnScreen(loc_int);
        } catch (NullPointerException npe) {
            return null;
        }
        Rect location = new Rect();
        location.left = loc_int[0];
        location.top = loc_int[1];
        location.right = loc_int[0] + v.getWidth();
        location.bottom = loc_int[1] + v.getHeight();
        return location;
    }