java - Android 如何在 android iframe webview 中传递 url？

Question

Android 如何在android iframe webview 中传递url？ 我正在尝试从服务器动态传递 url 所以我做什么

if(ResponseProduct.video!=null) {

                            String html = "<iframe width=\"450\" height=\"260\" src=\""+ResponseProduct.video+"\" ></iframe>";
                            WebView webView = (WebView) view.findViewById(R.id.video);
                            webView.setVisibility(View.VISIBLE);
                            webView.getSettings().setPluginState(WebSettings.PluginState.ON);
                            webView.getSettings().setPluginState(WebSettings.PluginState.ON_DEMAND);
                            webView.getSettings().setJavaScriptEnabled(true);
                            webView.getSettings().setJavaScriptCanOpenWindowsAutomatically(true);
                            webView.getSettings().setSupportMultipleWindows(true);
                            webView.setWebChromeClient(new WebChromeClient());
                            webView.setHorizontalScrollBarEnabled(false);
                            webView.loadData(html, "text/html; video/mpeg", "UTF-8");

                        } 

Answer 1

您需要将 String url 路径放在 src 中，例如:

 String videoPath="http://api.thingspeak.com/channels/31592/charts/1?width=450&height=260&results=60&dynamic=true\\";

 String html = "<iframe width=\"450\" height=\"260\" style=\"border: 1px solid #cccccc;\" src=\""+videoPath+" ></iframe>";

如果 videoUrl 为 null 或无效则您的页面未加载则您需要隐藏 webView

代码如下:

private boolean isValidUrl(String url) {
      Pattern p = Patterns.WEB_URL;
      Matcher m = p.matcher(url.toLowerCase());
      if(m.matches())
         return true;
      else
        return false;
}

然后加载到webView

 webview.getSettings().setJavaScriptEnabled(true);
if(videoPath!=null && isValidUrl(videoPath)
{
mWebView.setVisibility(View.VISIBLE); 
webview.loadData(html, "text/html", null);
    }

else
webview.setVisibility(View.GONE);