java - 有什么方法可以根据用户输入编辑 URI？

Question

我有一个从 URI 接收信息的 HTTP GET。 URI 用于 Google 购物。

https://www.googleapis.com/shopping/search/v1/public/products?key=key&country=US&q=digital+camera&alt=atom

(遗漏了我的 key )。

有什么方法可以改变它

q=digital+camera

用户在 EditText 中输入的任何内容？

基本上，我希望 EditText 更改在 Google 购物上搜索的内容。

第一个屏幕，带有用于搜索查询的 EditText 的 ProductSearchEntry:

ProductSearchEntry 代码

public class ProductSearchEntry extends Activity{
protected void onCreate(Bundle savedInstanceState){
    super.onCreate(savedInstanceState);
    setContentView(R.layout.productsearchentry);

    Button search = (Button) findViewById(R.id.searchButton);

    search.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            Intent searchIntent = new Intent(getApplicationContext(), ProductSearch.class);
                startActivity(searchIntent);
        }
    });
    }
}

然后，我有第二个类，ProductSearch，没有图片，只有这段代码:

public class ProductSearch extends Activity{
protected void onCreate(Bundle savedInstanceState){
    super.onCreate(savedInstanceState);
    setContentView(R.layout.productsearchresults);
     EditText searchQuery = (EditText) findViewById(R.id.searchQuery);

        ProductSearchMethod test = new ProductSearchMethod();
        String entry;
        TextView httpStuff = (TextView) findViewById(R.id.httpTextView);
        try {
            entry = test.getSearchData(searchQuery.getText().toString());
            httpStuff.setText(entry);
              } catch (Exception e) {
                        e.printStackTrace();
    }
}
}

它引用 ProductSearchMethod 类，该类由一个 TextView 组成，该 TextView 已更改为在 HTTP GET 中收到的代码:

代码:

public class ProductSearchMethod {

public String getSearchData(String query) throws Exception{
    BufferedReader in = null;
    String data = null;
    try{
        HttpClient client = new DefaultHttpClient();
        URI site = new URI("https://www.googleapis.com/shopping/search/v1/public/products?key=key&country=US&q="+query.replace(" ","+")+"&alt=atom");
     HttpGet request = new HttpGet();
    request.setURI(site);
    HttpResponse response = client.execute(request);
    in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
    StringBuffer sb = new StringBuffer("");
    String l = "";
    String nl = System.getProperty("line.seperator");
    while((l = in.readLine()) !=null){
        sb.append(l + nl);
    }
    in.close();
    data = sb.toString();
    return data;
    }finally{
        if (in != null){
            try{
                in.close();
                return data;
            }catch (Exception e){
                e.printStackTrace();
                }
            }
        } 
    }
}

ProductSearchMethod 运行良好，但它不会将文本从“加载项”更改为网站代码。我之前让它工作，但后来我尝试编辑它搜索的内容(所有这些 ^)，现在它没有改变。

Answer 1

像这样修改你的代码

public class ProductSearchEntry extends Activity{ 
protected void onCreate(Bundle savedInstanceState){ 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.productsearchentry); 
    EditText etSearch = (EditText) findViewById(id of your edittext);
    Button search = (Button) findViewById(R.id.searchButton); 

    search.setOnClickListener(new View.OnClickListener() { 

        @Override 
        public void onClick(View v) { 
            //while calling intent 

            Intent searchIntent = new Intent(getApplicationContext(), ProductSearch.class); 
            searchIntent.putExtra("searchText",etSearch.getText().toString());
            startActivity(searchIntent); 
        } 
    }); 
    } 
} 

和另一个类似的 Activity ，

public class ProductSearch extends Activity{     
protected void onCreate(Bundle savedInstanceState){     
    super.onCreate(savedInstanceState);     
    setContentView(R.layout.productsearchresults);     
        String searchQuery = getIntent().getStringExtra("searchText");     
        ProductSearchMethod test = new ProductSearchMethod();     
        String entry;     
        TextView httpStuff = (TextView) findViewById(R.id.httpTextView);     
        try {     
            entry = test.getSearchData(searchQuery);     
            httpStuff.setText(entry);     
              } catch (Exception e) {     
                        e.printStackTrace();     
    }     
}     
}