android - 我如何在 android 中返回到我的 gl 屏幕。我曾尝试跳出并在我的代码中使用 xml 布局

Question

好吧，我在这个网站上到处都看了，但没有找到我的问题的答案。我正在尝试制作游戏，此时我需要从屏幕上获取用户信息。我已经完成了整个游戏，只需要这部分就可以继续前进。我正从屏幕类转到 xml 布局，似乎无法回到我的屏幕类以移动到游戏的下一部分。使用布局似乎比我自己构建文本框更容易。这是我的代码。

import android.app.Activity;
import android.content.Intent;
import android.util.Log;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.EditText;
import android.widget.RadioButton;

import com.wright.knightsattack.framework.Game;
import com.wright.knightsattack.framework.gl.Camera2D;
import com.wright.knightsattack.framework.gl.SpriteBatcher;
import com.wright.knightsattack.framework.impl.GLScreen;
import com.wright.knightsattack.framework.math.Vector2;

public class NewCharacterInfo extends GLScreen
{
EditText Name, Strength, Dexterity, Agility, Intelligence, Charisma;
RadioButton Sex;
int intStrength, intDexterity, intAgility, intIntelligence, intCharisma;
Button Done_BTN;
Camera2D guiCam;
SpriteBatcher batcher;
Vector2 animPoint;
Game gameIn;
Activity activity;
Intent gameIntent;
Boolean enterInfo = true;

public NewCharacterInfo(Game game)
{
    super(game);
    gameIn = game;
    activity = (Activity) game;
}

@Override
public void resume()
{

}

@Override
public void update(float deltaTime)
{

    if (enterInfo == true)
    {
        runInfo();
    } else
    {

        newScreen();
        return;
    }
}

public void runInfo()
{
    activity.runOnUiThread(new Runnable()
    {
        public void run()
        {

            activity.setContentView(R.layout.new_character_info);

            Name = (EditText) activity.findViewById(R.id.editTextName);
            Sex = (RadioButton) activity.findViewById(R.id.radioButton1);
            Strength = (EditText) activity.findViewById (R.id.editTextStrength);
            Dexterity = (EditText) activity.findViewById(R.id.editTextDexterity);
            Agility = (EditText) activity.findViewById(R.id.editTextAgility);
            Intelligence = (EditText) activity.findViewById(R.id.editTextIntelligence);
            Charisma = (EditText) activity.findViewById(R.id.editTextCharisma);

            Done_BTN = (Button) activity.findViewById(R.id.done);
            Done_BTN.setOnClickListener(new OnClickListener()
            {
                public void onClick(View v)
                {
                    Log.e("Click check", "Inside");
                    if (v.getId() == R.id.done)
                    {
                        Log.e("Click check", "Try to change screen");
                        intStrength = Integer.parseInt(Strength.getText().toString());
                        intDexterity = Integer.parseInt(Dexterity.getText().toString());
                        intAgility = Integer.parseInt(Agility.getText().toString());
                        intIntelligence = Integer.parseInt(Intelligence.getText().toString());
                        intCharisma = Integer.parseInt(Charisma.getText().toString());
                        Settings.addCharacterStats(Name.getText().toString(), Sex.getText().toString(), 0, 0, 0, 0, 200, intStrength, intIntelligence, intDexterity, intAgility, intCharisma, 0, 0, 0, 0, 0, 0);

                        // gameIntent = activity.getIntent();
                        enterInfo = false;
                        update(0);
                        return;
                    }

                }
            });
        }

    });
}

public void newScreen()
{

    Settings.save(gameIn.getFileIO());
    gameIn.setScreen(new SplashHelmScreen(gameIn));
    Log.e("", "check" + gameIn);
    return;
}

@Override
public void present(float deltaTime)
{

}

@Override
public void pause()
{

}

@Override
public void dispose()
{

}
}

将弹出 xml 屏幕，我可以在所有文本框中输入信息，但是当点击完成按钮时出现错误，这是我从 logcat 得到的错误。

01-09 11:04:38.038: E/libEGL(1743): call to OpenGL ES API with no current context (logged once per thread)

感谢您的帮助，我真的很感激我已经为此苦苦挣扎了几天。

没关系，我修复了它，我只是创建了一个新的 Intent ，然后当输入信息时，我在 Activity 上调用 finish() 并跳转到我的当前屏幕。

Answer 1

如果您想返回主屏幕，您有两种选择:

@Override
public void onBackPressed() {

或者如果你有一个按钮:

Button btn =(Button)findViewById(R.id.btn); btn.setonClickListener(this);

@覆盖 public void onClick(View v) {

    switch (v.getId()) {

案例 R.id.btn: kill_activity(); 休息；

}}

void kill_activity() {

完成();

干杯，