我正在尝试从 Android java 脚本(到我的 php)将文件和数据发布到我的服务器，看来我已经差不多了，但是请有人帮助我，因为我似乎无法格式化名称/值部分(文件上传完美，但它不发送名称值 :( )
Java:
try{
int serverResponseCode = 0;
final String upLoadServerUri = "http://myUrl/upload_file_functions.php";
String fileName = "/mnt/sdcard/myFile.dat";
HttpURLConnection conn = null;
DataOutputStream dos = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
File sourceFile = new File("/mnt/sdcard/myFile.dat");
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("file", fileName);
conn.setRequestProperty("gmail", names[0]);
conn.setRequestProperty("phn", phn);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"file\";filename=\""
+ fileName + "\"" + lineEnd);
dos.writeBytes(twoHyphens + boundary + lineEnd);
String data = URLEncoder.encode("gmail", "UTF-8") + "=" + URLEncoder.encode(names[0], "UTF-8");
dos.writeBytes(data);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"" + names[0] + "\"" + lineEnd);
dos.writeBytes("Content-Type: text/plain"+lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(names[0]);
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
//*************************
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : "
+ serverResponseMessage + ": " + serverResponseCode);
if(serverResponseCode == 200){
// it worked !
}
//close the streams //
fileInputStream.close();
dos.flush();
dos.close();
}catch (Exception e){
}
它不起作用，FILE 发送正常，但我无法获得要发送的该死的 key /名称(“gmail:”names[0])我也试过:
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("gmail", names[0]);
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"file\";filename=\""
+ fileName + "\"" + lineEnd);
dos.writeBytes(twoHyphens + boundary + lineEnd);
不起作用。我试过:
dos.writeBytes("Content-Disposition: form-data; name=\"gmail\";filename=\""+ names[0] + "\"" + lineEnd);
没用!卧槽!我用 C++ 和 Python 编程多年，这很简单!但我想不通，我需要帮助，如果你知道怎么做，请告诉我，因为我花了两天时间用头撞墙。我并不懒惰，我在这上面花了 32 多个小时，求求你了..
我想要发生的事情:发送要上传的文件以及值(名称=gmail 值=名称[0]；名称=phn 值=phn)，以便电子邮件与我服务器上的文件相关联. 发生了什么:文件上传正常，但数据未传递(未发送名称/值对)
PHP:
<?php
set_time_limit(100);
//need to get email also (gmail address of user)
//************************************************
if ($_FILES["file"]["error"] > 0)
{
echo "Error: " . $_FILES["file"]["error"] . "<br>";
}
else
{
echo "Upload: " . $_FILES["file"]["name"] . "<br>";
echo "Type: " . $_FILES["file"]["type"] . "<br>";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " kB<br>";
echo "Stored in: " . $_FILES["file"]["tmp_name"];
move_uploaded_file($_FILES["file"]["tmp_name"],
"upload/" . $_FILES["file"]["name"]);
echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
}
}
function Three(){
$to = 'me@email.com';
$subject = $_POST['phn'] . " " . $_POST['gmail'];
$bound_text = "file";
$bound = "--".$bound_text."\r\n";
$bound_last = "--".$bound_text."--\r\n";
$headers = "From: me@email.com\r\n";
$headers .= "MIME-Version: 1.0\r\n"
."Content-Type: multipart/mixed; boundary=\"$bound_text\"";
$message .= "If you can see this MIME than your client doesn't accept MIME types!\r\n"
.$bound;
$message .= "Content-Type: text/html; charset=\"iso-8859-1\"\r\n"
."Content-Transfer-Encoding: 7bit\r\n\r\n"
."hey my <b>good</b> friend here is a picture of regal beagle\r\n"
.$bound;
$file = file_get_contents("http://myURL/upload/myFile.dat");
$message .= "Content-Type: image/jpg; name=\"myFile.dat\"\r\n"
."Content-Transfer-Encoding: base64\r\n"
."Content-disposition: attachment; file=\"myFile.dat"\r\n"
."\r\n"
.chunk_split(base64_encode($file))
.$bound_last;
@mail($to, $subject, $message, $headers);
//delete files
$fileArray=array($_FILES["file"]["name"],"myfile.dat","myfile.dat");
foreach($fileArray as $value){
if(file_exists($value)){
unlink($value);
}
}
chdir($old_path);
}
function runAll(){
One();
Two();
Three();
}
runAll();
$randx=null;
unset($randx);
?>
请帮忙! JAVA 不发送 name='gmail' value=names[0]，也不发送 name='phn' value=phn ..
最佳答案
您真的应该仔细阅读一些内容:HTTP(以及请求 header 字段和帖子正文之间的区别)，以及多部分/表单数据帖子正文的结构。
这个:
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("file", fileName);
conn.setRequestProperty("gmail", names[0]);
conn.setRequestProperty("phn", phn);
发送一些请求 header ，这适用于Content-Type 等，但不一定适用于您发布的数据。丢失除 Content-Type 行之外的所有内容。
这个:
dos.writeBytes(twoHyphens + boundary + lineEnd);
是开始发布字段(或文件)的正确方法，您应该为每个发布的字段输出它。
这个:
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
所有字段都已发送的信号，您应该将其作为最后一行发送。
要么使用 Wireshark 之类的东西来查看您的最终请求是什么样的(任何一方都可以；执行请求的设备或处理它的服务器)，或者记录您的请求以便您检查它，看看它是否完美.它必须近乎完美，网络服务器/php 才能正确处理它。
关于java - HttpURLConnection 和用数据写入文件，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/23188300/