我需要一个数组，列出不同数组中每个元素的字母数:
words = ["first", "second", "third", "fourth"]
我尝试为每个元素的长度创建一个变量。这:
first = words[0].length
second = words[1].length
third = words[2].length
fourth = words[3].length
letters = [first, second, third, fourth]
puts "#{words}"
puts "#{letters}"
puts "first has #{first} characters."
puts "second has #{second} characters."
puts "third has #{third} characters."
puts "fourth has #{fourth} characters."
输出:
["first", "second", "third", "fourth"]
[5, 6, 5, 6]
first has 5 characters.
second has 6 characters.
third has 5 characters.
fourth has 6 characters.
但这似乎是一种低效的做事方式。有没有更可靠的方法来做到这一点？
最佳答案
跳过字长数组并使用 Array#each :
words.each { |word| puts "#{word} has #{word.size} letters" }
#first has 5 letters
#second has 6 letters
#third has 5 letters
#fourth has 6 letters
如果由于某种原因您仍然需要字大小数组，请使用 Array#map :
words.map(&:size) #=> [5, 6, 5, 6]
关于arrays - 另一个数组中字符串长度的数组，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/48969796/