ruby-on-rails - 没有将 nil 隐式转换为 String。数据库 View _cti

标签 ruby-on-rails ruby inheritance class-table-inheritance

我使用dbview_cti gem 用于创建类表继承 (CTI)。我有两个类 Person(抽象类)和 Client(继承 Person)。

问题:

当我尝试 make rake db:migrate 时,控制台写出此错误:

StandardError: An error has occurred, this and all later migrations canceled:

    no implicit conversion of nil into String ../postgresql/utils.rb:24:in `quote_ident'

模范人物

class Person < ActiveRecord::Base
  self.abstract_class = true
  cti_base_class
end

模型客户端

class Client < Person
  cti_derived_class
end

迁移create_people

class CreatePeople < ActiveRecord::Migration
  def self.up
    create_table :persons do |t|
      t.string :pesel, null: false
      t.string :first_name, null: false
      t.string :last_name, null: false
      t.string :email, null: false
      t.date :data_of_birth, null: false
      t.string :password_digest, null: false
      t.timestamps null: false
    end
  end

  def self.down
    drop_table :persons
  end
end

迁移create_clients

class CreateClients < ActiveRecord::Migration
  def change
    create_table :clients do |t|
      t.references :person
      t.timestamps null: false
    end

    cti_create_view('Client')
  end
end

有关错误的更多详细信息:

>     == 20160223135814 CreateClients: migrating ====================================
>     -- create_table(:clients)
>        -> 0.0348s
>     -- cti_create_view("Client")
>     rake aborted!
>     StandardError: An error has occurred, this and all later migrations canceled:
>     
>     no implicit conversion of nil into String/home/lukas/.rvm/gems/ruby-2.2.3/gems/activerecord-4.2.5.1/lib/active_record/connection_adapters/postgresql/utils.rb:24:in
> `quote_ident'
>     /home/lukas/.rvm/gems/ruby-2.2.3/gems/activerecord-4.2.5.1/lib/active_record/connection_adapters/postgresql/utils.rb:24:in
> `quoted'
>     /home/lukas/.rvm/gems/ruby-2.2.3/gems/activerecord-4.2.5.1/lib/active_record/connection_adapters/postgresql/quoting.rb:31:in
> `quote_table_name'
>     /home/lukas/.rvm/gems/ruby-2.2.3/gems/activerecord-4.2.5.1/lib/active_record/connection_adapters/postgresql_adapter.rb:738:in `column_definitions'
>     /home/lukas/.rvm/gems/ruby-2.2.3/gems/activerecord-4.2.5.1/lib/active_record/connection_adapters/postgresql/schema_statements.rb:186:in
> `columns'
>     /home/lukas/.rvm/gems/ruby-2.2.3/gems/activerecord-4.2.5.1/lib/active_record/connection_adapters/schema_cache.rb:43:in
> `columns'

知道哪里出了问题吗?

最佳答案

您的 Person 类被标记为抽象类,因此其 table_namenil。一般来说,添加了 Abstract_class,这样 gem 就可以定义自己的 ActiveRecord::Base 子类,然后可以在应用程序中继承这些子类,而不会导致 STI 逻辑进入。您可以将其设置为非抽象,也可以将表名称设置为继承:

class Person < ActiveRecord::Base
  self.abstract_class = true
  self.table_name = 'people'
  cti_base_class
end

关于ruby-on-rails - 没有将 nil 隐式转换为 String。数据库 View _cti,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35584788/

相关文章:

ruby-on-rails - ActionController::Racers 中的 UrlGenerationError#new

c++ - 将参数传递给父类(super class)构造函数

ruby - 在 ruby​​ 1.9 中调试

c++ - 派生类中的抽象类实现

javascript - 什么时候真正使用对象的 `.constructor`属性

ruby-on-rails - 如何按 DESC 限制订单,然后按 ( :id)?

ruby-on-rails - 通过电子邮件作为附件发送回形针文件 - Rails

ruby-on-rails - 如何使用 rails 3 中的命名路由覆盖范围路由?

javascript - Rails Angular 和实时更新

ruby - 设计之外的 Omniauth 策略