取自documentation对于 Proc#lambda?:
Returns true for a Proc object for which argument handling is rigid. Such procs are typically generated by lambda.
什么是“刚性参数”处理？
最佳答案
如果传递了错误数量的参数，Lambdas 将引发一个 ArgumentError，而 Proc.new 则不会。
例子:
lam = ->(x){ "OK" }
lam.lambda? # => true
lam.call # => ArgumentError
lam.call(1) # => OK
proc = Proc.new { |x| "OK" }
proc.lambda? # => false
proc.call # => OK
proc.call(1) # => OK
proc.call(1,2,3,4,5,6,7,8,9) # => OK
关于ruby - 参数处理为 "rigid"是什么意思？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/41388995/