我想让字段由另一个字段解析。
我有一个根据一些参数生成的列表,想更新总字段
我的方法可能不正确。
显然,我试图避免重新运行相同的数据库查询并在查询字符串中向上传递一个级别的过滤器。
因此假设我的查询使用以下 ruby 类型:
Types::PostListType = GraphQL::ObjectType.define do
name 'PostList'
field :total, !types.Int, default_value: 0 # <-- this is what I'd like to update in :posts resolution
field :page, !types.Int, default_value: 0 # <-- this is what I'd like to update in :posts resolution
field :per_page, !types.Int, default_value: 0 # <-- this is what I'd like to update in :posts resolution
field :posts, types[Types::PostType] do
argument :page, types.Int, default_value: 1
argument :per_page, types.Int, default_value: 10 # <-- also need a limit here (hence why I need a field to tell what's been used in the end)
argument :filter, types.String, default_value: ''
resolve ->(user, *_args) {
posts = function_to_filter(args[:filter])
# how do I update total with posts.count here?
posts.paginate(page: args[:page], per_page: args[:per_page])
# how do I update per_page and page?
}
end
end
我的查询是这样的:
query ProspectList {
posts(filter:"example", page: 2) {
total
page
per_page
posts {
id
...
}
}
}
最佳答案
您想要的是在不重新运行数据库查询的情况下返回包含总页数、页数、每页数的帖子。
我想修改查询定义,因为posts、total、page、per_page在类型上要合并。
像这样:Types::PostListType
Types::PostListType = GraphQL::ObjectType.define do
name 'PostList'
field :total, !types.Int
field :page, !types.Int
field :per_page, !types.Int
field :posts, types[Types::PostType]
end
然后在 resolve 中返回包含posts, total, page, per_page
的对象Types::QueryType = GraphQL::ObjectType.define do
name "Query"
field :postlist, Types::PostListType do
argument :page, types.Int, default_value: 1
argument :per_page, types.Int, default_value: 1
argument :filter, types.String
resolve ->(_obj, args, _ctx) {
result = Post.paginate(page: args[:page], per_page: args[:per_page])
Posts = Struct.new(:posts, :page, :per_page, :total)
Posts.new(
result,
args[:page],
args[:per_page],
result.total_entries
)
}
end
end
也可以定义一个对象并返回。 Wrapper::PostList
module Wrapper
class PostList
attr_accessor :posts, :total, :page, :per_page
def initialize(posts, page, per_page)
@posts = posts
@total = posts.total_entries
@page = page
@per_page = per_page
end
end
end
...
field :postlist, Types::PostListType do
argument :page, types.Int, default_value: 1
argument :per_page, types.Int, default_value: 1
argument :filter, types.String
resolve ->(_obj, args, _ctx) {
Wrapper::PostList.new(Post.paginate(page: args[:page], per_page: args[:per_page]), args[:page], args[:per_page])
}
...
关于ruby - 我怎样才能让一个字段更新/更改另一个字段?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52935158/