Javascript 排序和排序

Question

所以我有这个数组

[ 'vendor/angular/angular.min.js',
  'vendor/angular-nice-bar/dist/js/angular-nice-bar.min.js',
  'vendor/angular-material/modules/js/core/core.min.js',
  'vendor/angular-material/modules/js/backdrop/backdrop.min.js',
  'vendor/angular-material/modules/js/dialog/dialog.min.js',
  'vendor/angular-material/modules/js/button/button.min.js',
  'vendor/angular-material/modules/js/icon/icon.min.js',
  'vendor/angular-material/modules/js/tabs/tabs.min.js',
  'vendor/angular-material/modules/js/content/content.min.js',
  'vendor/angular-material/modules/js/toolbar/toolbar.min.js',
  'vendor/angular-material/modules/js/input/input.min.js',
  'vendor/angular-material/modules/js/divider/divider.min.js',
  'vendor/angular-material/modules/js/menu/menu.min.js',
  'vendor/angular-material/modules/js/select/select.min.js',
  'vendor/angular-material/modules/js/radioButton/radioButton.min.js',
  'vendor/angular-material/modules/js/checkbox/checkbox.min.js',
  'vendor/angular-material/modules/js/switch/switch.min.js',
  'vendor/angular-material/modules/js/tooltip/tooltip.min.js',
  'vendor/angular-material/modules/js/toast/toast.min.js',
  'vendor/angular-clipboard/angular-clipboard.js',
  'vendor/angular-animate/angular-animate.min.js',
  'vendor/angular-aria/angular-aria.min.js',
  'vendor/angular-messages/angular-messages.min.js',
  'vendor/angular-ui-router/release/angular-ui-router.js',
  'src/app/about/about.js',
  'src/app/hekate.cfg.js',
  'src/app/hekate.ctrl.js',
  'src/app/hekate.module.js',
  'src/app/home/home.js',
  'src/app/user/dialog/user.signIn.ctrl.js',
  'src/app/user/dialog/user.signIn.module.js',
  'src/app/user/user.cfg.js',
  'src/app/user/user.ctrl.js',
  'src/app/user/user.module.js',
  'src/common/services/toast.service.js',
  'templates-common.js',
  'templates-app.js'
]

并以上述数组中的以下部分为例:

[ 
  'src/app/hekate.cfg.js',
  'src/app/hekate.ctrl.js',
  'src/app/hekate.module.js',
]

我想这样排序

[ 
  'src/app/hekate.module.js',
  'src/app/hekate.cfg.js',
  'src/app/hekate.ctrl.js',
]

所以我想要的更具体的是在那个字符串重复的数组中找到并在检查结束后是否有 [.cfg.js, .ctrl.js, .module.js] 并自动将它们排序为 [ .module.js, .cfg.js, .ctrl.js]

有人可以帮我吗？

Answer 1

单一排序建议。

var array = ['src/app/about/about.js', 'src/app/hekate.cfg.js', 'src/app/hekate.ctrl.js', 'src/app/hekate.module.js', 'src/app/home/home.js', 'src/app/user/dialog/user.signIn.ctrl.js', 'src/app/user/dialog/user.signIn.module.js', 'src/app/user/user.cfg.js', 'src/app/user/user.ctrl.js', 'src/app/user/user.module.js'];

array.sort(function (a, b) {
    function replaceCB(r, a, i) { return r.replace(a, i); }

    var replace = ['.module.js', '.cfg.js', '.ctrl.js'];            
    return replace.reduce(replaceCB, a).localeCompare(replace.reduce(replaceCB, b));
});

document.write('<pre>' + JSON.stringify(array, 0, 4) + '</pre>');

为了防止太多替换，我建议看看 sorting with map .