问题类似于:How can I check that two objects have the same set of property names?但只有一个区别
我要检查:
var objOne = {"a":"one","b":"two","c":{"f":"three_one"}};
var objTwo = {"a":"four","b":"five","c":{"f":"six_one"}};
所有级别的键都相同吗?
例如 deepCheckObjKeys(objOne, objTwo)
将返回 true
其中 deepCheckObjKeys(objOne, objThree)
返回 false
,如果:
var objThree = {"a":"four","b":"five","c":{"g":"six_one"}};
因为 objThree.a.c.f
在 objThree 中是 undefined
。
像这样的函数:
'使用严格';
function objectsHaveSameKeys() {
for (var _len = arguments.length, objects = Array(_len), _key = 0; _key < _len; _key++) {
objects[_key] = arguments[_key];
}
var allKeys = objects.reduce(function (keys, object) {
return keys.concat(Object.keys(object));
}, []);
var union = new Set(allKeys);
return objects.every(function (object) {
return union.size === Object.keys(object).length;
});
}
只检查第一层。
PS: objectsHaveSameKeys() 等效于 ES6:
function objectsHaveSameKeys(...objects):boolean {
const allKeys = objects.reduce((keys, object) => keys.concat(Object.keys(object)), []);
const union = new Set(allKeys);
return objects.every(object => union.size === Object.keys(object).length);
}
最佳答案
如果属性的值是对象,我会进行递归检查。
这里有一个有趣的问题;实际上,有(至少)两个:
- 如果其中一个“对象”为
null
而另一个没有属性怎么办?true
还是false
? - 如果其中一个对象具有
{a: null}
而另一个对象具有{a: 17}
怎么办?true
还是false
? - 如果其中一个对象具有
{a: null}
而另一个对象具有{a: {}}
怎么办?true
还是false
?
为了本示例的目的,我将 null
视为没有属性的对象,但它非常很大程度上取决于您的用例。我至少可以想到另外两种方法(null
除了 null
之外什么都不匹配,或者 null
除了什么都不匹配一个非对象,即使该对象没有自己的属性)并且可能还有其他属性。
查看评论:
const deepSameKeys = (o1, o2) => {
// Both nulls = same
if (o1 === null && o2 === null) {
return true;
}
// Get the keys of each object
const o1keys = o1 === null ? new Set() : new Set(Object.keys(o1));
const o2keys = o2 === null ? new Set() : new Set(Object.keys(o2));
if (o1keys.size !== o2keys.size) {
// Different number of own properties = not the same
return false;
}
// Look for differences, recursing as necessary
for (const key of o1keys) {
if (!o2keys.has(key)) {
// Different keys
return false;
}
// Get the values and their types
const v1 = o1[key];
const v2 = o2[key];
const t1 = typeof v1;
const t2 = typeof v2;
if (t1 === "object") {
if (t2 === "object" && !deepSameKeys(v1, v2)) {
return false;
}
} else if (t2 === "object") {
// We know `v1` isn't an object
return false;
}
}
// No differences found
return true;
};
// Checking your example
const objOne = {"a": "one", "b": "two", "c": {"f": "three_one"}};
const objTwo = {"a": "four", "b": "five", "c": {"f": "six_one"}};
const objThree = {"a": "four", "b": "five", "c": {"g": "six_one"}};
console.log("objOne vs. objTwo: ", deepSameKeys(objOne, objTwo)); // true
console.log("objTwo vs. objThree: ", deepSameKeys(objTwo, objThree)); // false
// `null` checks
console.log("{a: null} vs. {a: 17} ", deepSameKeys({a: null}, {a: 17})); // true
console.log("{a: null} vs. {a: {}} ", deepSameKeys({a: null}, {a: {}})); // true -- depending on your use case, you may want this to be false
console.log("{a: null} vs. {a: {x:1}} ", deepSameKeys({a: null}, {a: {x:1}})); // false
// Differing value type check
console.log("{a: 1} vs. {a: '1'}} ", deepSameKeys({a: 1}, {a: '1'})); // true
关于JavaScript:深度检查对象具有相同的键,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41802259/