javascript - 类型错误 : $timeout is not a function

Question

这里发生了什么:

我希望“取消预订”按钮在单击后超时。第一次单击时，它会更改为显示“确认取消”按钮。几秒钟后返回“取消预订”。

我的控制台给我:

TypeError: $timeout is not a function

我正在使用 AngularJS $timeout:

Controller :

'use strict';

module.controller('ReservationItemCtrl', ['$scope', '$stateParams', '$RPC',
    function($scope, $stateParams, $RPC, $timeout) {


 ......other stuff.......
 ......other stuff.......

    $scope.toggleCancelReservation = function(reservation) {
        reservation.clickedcancel = true;
        $timeout(function(){reservation.clickedcancel = false}, 4000);
    };
}
]);

模板:

  <button ng-show="!reservation.value.deleted && !deleted.value"
          class="btn btn-danger" 
          ng-show="canCancel(reservation)" ng-if="!reservation.clickedcancel" ng-click="toggleCancelReservation(reservation)">
    Cancel With Refund
  </button>
  <button type="button" class="btn btn-danger" ng-if="reservation.clickedcancel == true" ng-click="deleteReservation();" style="margin-top: -4px;">
    Confirm Cancellation
  </button>

我准确地让按钮在第一次点击时切换，如果再次点击它会正确取消/删除预订，但如果我在第一次点击后没有做任何事情，超时永远不会将其返回到原始按钮。在我的控制台中，出于某种原因，我看到 $timeout 不是一个函数？我把它包含在我的 Controller 中。我错过了什么吗？

Answer 1

您忘记了 $timeout 的内联符号:

'use strict';
module.controller('ReservationItemCtrl', ['$scope', '$stateParams', '$RPC', '$timeout',
    function ($scope, $stateParams, $RPC, $timeout) {
            ......other stuff.......
            ......other stuff.......
        $scope.toggleCancelReservation = function (reservation) {
            reservation.clickedcancel = true;
            $timeout(function () {
                reservation.clickedcancel = false
            }, 4000);
        };
    }
]);