我有一个对象数组。我想深入复制对象数组并对每个对象进行一些更改。我想在不修改原始数组或该数组中的原始对象的情况下执行此操作。
这就是我的做法。然而,作为 JavaScript 的新手,我想确保这是一个好的方法。
有更好的方法吗?
const users =
[
{
id : 1,
name : 'Jack',
approved : false
},
{
id : 2,
name : 'Bill',
approved : true
},
{
id : 3,
name : 'Rick',
approved : false
},
{
id : 4,
name : 'Rick',
approved : true
}
];
const users2 =
users
.map(
(u) =>
{
return Object.assign({}, u);
}
)
.map(
(u) =>
{
u.approved = true;
return u;
}
);
console.log('New users2 array of objects:')
console.log(users2);
console.log('This was original users array is untouched:')
console.log(users);
输出:
New users2 array of objects:
[ { id: 1, name: 'Jack', approved: true },
{ id: 2, name: 'Bill', approved: true },
{ id: 3, name: 'Rick', approved: true },
{ id: 4, name: 'Rick', approved: true } ]
This was original users array is untouched:
[ { id: 1, name: 'Jack', approved: false },
{ id: 2, name: 'Bill', approved: true },
{ id: 3, name: 'Rick', approved: false },
{ id: 4, name: 'Rick', approved: true } ]
最佳答案
对于单次传递,您可以使用 Object.assign
以及更改后的属性。
const users = [{ id: 1, name: 'Jack', approved: false }, { id: 2, name: 'Bill', approved: true }, { id: 3, name: 'Rick', approved: false }, { id: 4, name: 'Rick', approved: true }];
const users2 = users.map(u => Object.assign({}, u, { approved: true }));
console.log(users2);
console.log(users);
.as-console-wrapper { max-height: 100% !important; top: 0; }
更新传播属性。
const users = [{ id: 1, name: 'Jack', approved: false }, { id: 2, name: 'Bill', approved: true }, { id: 3, name: 'Rick', approved: false }, { id: 4, name: 'Rick', approved: true }];
const users2 = users.map(u => ({ ...u, approved: true }));
console.log(users2);
console.log(users);
.as-console-wrapper { max-height: 100% !important; top: 0; }
关于javascript - 复制对象数组并在不修改原始数组的情况下进行更改,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45512723/