javascript - 继承和 TypeScript 错误 : X is not a constructor function type

Question

我有一个父类(super class)，我希望从中继承其他两个类。下面列出了这些类(class)。当我编译时，试图继承的两个类提示父类(super class)(给出相同的错误): “[类文件路径(在本例中为 A)] 不是构造函数类型”

A.ts

export class A
{
    //private fields...

    constructor(username: string, password: string, firstName: string,
        lastName: string, accountType: string) 
    {
        // initialisation
    }
}

B.ts

import A = require('./A);
export class B extends A
{
    constructor(username: string, password: string, firstName: string,
        lastName: string, accountType: string) 
    {
        super(username, password, firstName, lastName, accountType);
    }
}

C.ts

import A = require('./A );
export class C extends A
{
    constructor(username: string, password: string, firstName: string,
        lastName: string, accountType: string) 
    {
        super(username, password, firstName, lastName, accountType);
    }
}

这很简单，但是 C 类和 B 类无法编译。我在网上看到的所有示例都没有用于编写这些类/构造函数的任何其他语法。我试图遵循惯例，但似乎无法让它发挥作用。

Answer 1

替换

import A = require('./A');

与

import { A } from './A';

或

import moduleA = require('./A');

export class B extends moduleA.A {
  // ...
}