javascript:如何在没有jquery或其他库的情况下将表单数据序列化为字符串

Question

如何在没有 jquery 或其他库的情况下以 ajax 方式发布表单数据。

我想定义一个ajaxForm函数，它可以序列化表单数据和AJAX post，然后通过javascript回调。

如果我有下面的表格:

<form action="url" method="POST">
<table>
<tr><td>label...</td><td><input name="input1" type="text"/></td></tr>
<tr><td>label...</td><td><input name="input2" type="checkbox"/></td></tr>
<tr><td>label...</td><td><select name="input3"><options....></select></td></tr>
</table>
</form>

然后我通过 javascript 获取了表单元素，然后我将表单元素和回调函数传递给 ajaxForm(form, callback) 函数。

谁能举个例子？非常感谢......

更新:我最大的问题是如何序列化表单数据？

再次更新:感谢大家的回复。问题已解决。

我已经将 jquery 表单插件迁移到纯 javascript。 我很高兴与大家分享。

https://github.com/guileen/ajaxform.js

button.onclick = function(){
  ajaxForm(form, function(xmlhttp){
    alert(xmlhttp.status);
    alert(xmlhttp.responseText);
  });
}

Answer 1

var http_request = false;
function makePOSTRequest(url, parameters) {
  http_request = false;
  if (window.XMLHttpRequest) { // Mozilla, Safari,...
     http_request = new XMLHttpRequest();
     if (http_request.overrideMimeType) {
        // set type accordingly to anticipated content type
        //http_request.overrideMimeType('text/xml');
        http_request.overrideMimeType('text/html');
     }
  } else if (window.ActiveXObject) { // IE
     try {
        http_request = new ActiveXObject("Msxml2.XMLHTTP");
     } catch (e) {
        try {
           http_request = new ActiveXObject("Microsoft.XMLHTTP");
        } catch (e) {}
     }
  }
  if (!http_request) {
     alert('Cannot create XMLHTTP instance');
     return false;
  }

  http_request.onreadystatechange = alertContents;
  http_request.open('POST', url, true);
  http_request.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
  http_request.setRequestHeader("Content-length", parameters.length);
  http_request.setRequestHeader("Connection", "close");
  http_request.send(parameters);
}

function alertContents() {
  if (http_request.readyState == 4) {
     if (http_request.status == 200) {
        //alert(http_request.responseText);
        result = http_request.responseText;
        document.getElementById('myspan').innerHTML = result;            
     } else {
        alert('There was a problem with the request.');
     }
  }
}

// call me
function get(obj) {
  var poststr = "mytextarea1=" + encodeURI( document.getElementById("mytextarea1").value ) +
                "&mytextarea2=" + encodeURI( document.getElementById("mytextarea2").value );
  makePOSTRequest('post.php', poststr);
}