arrays - 戈朗 : Could not understand how below code is executing

Question

下面是我查询的代码: 我有一个单维数组 a 当我打印 a[0][0] 时，我不明白为什么它返回字符 a 的 ascii 值:

package main
import (
        "fmt"
)

func main() {

        a := [3]string{"a","b","c"} 

        fmt.Println(a[0][0])
 }

输出:97

Answer 1

下面是如何打印ascii的代码示例

a := [3]string{"a","b","c"} 

for _, rune := range a {
   fmt.Println(rune)// It will print a,b,c
}

因为你在你的代码中使用了[0][0]，所以它是等价的

for _, rune := range a {
   fmt.Println(rune[0])// It will print 97,98,99
   // rune is equal to x := 'a'
   // when you write it like x := 'a' and
   // fmt.Println(x) the output is 97
}