go - 无法将图像转换为 []uint8

Question

如何从图像中提取原始 []uint8？

Answer 1

根据定义，8 位整数的大小为 8 位(或 1 个字节)。

(编辑删除错误信息，我将在下面为后代重新发布。)

输出的字符串表示不是每个数字一个字符 - 它是几个(例如，您首先列出的 int - 65 - 由 三个 个字符表示 -一个 6、一个 5 和一个空格。这将使预期大小增加三倍，从 300k 到 900k。

至于其余部分，我认为(如 icza 在评论中所说)图像压缩可能是罪魁祸首。

---

(我最初作为回答的一部分发布的无关信息是:

Go has two character types, byte and rune. A byte being used to store a character is the same size as a byte being used to store an integer - both are 8 bits. But a character being stored as a rune is going to be 32 bits (see https://www.callicoder.com/golang-basic-types-operators-type-conversion/). So, if the characters being written out are runes, that would explain a four-fold increase in size (because 32 / 8 = 4)...