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如果我将 int 数字存储到一个结构中，然后对它们应用除法，我就碰巧遇到了这种情况。精度会丢失。
func main() {
var x = 94911151
var y = 94911150
// If we use the value to calculate division directly, it would be fine
var result1 = float64(94911151)/94911150
var result2 = float64(x)/float64(y)
fmt.Println(result1, result2)
// If we pass the values directly as parameter into a function and then apply division, it would be fine
getParas(x,y)
// If we pass the values into a stuct, and then retrieve the value from struct, then apply division, the precision would be lost.
getLinearParas(Point{x,y},Point{0,0})
}
func getParas(a int, b int){
diffX := a -0
diffY := b-0
c:= float64(diffX) / float64(diffY)
fmt.Println(c)
}
type Point struct{
X int
Y int
}
func getLinearParas(point1 Point, point2 Point) {
diffX := point1.X - point2.X
diffY := point1.Y - point2.Y
a := float64(diffX) / float64(diffY)
fmt.Printf("diffY: %d; diffX:%d ; a:%f \n", diffY, diffX, a)
}
就像代码一样，如果我将 int 值放入一个结构中，然后对它们应用除法。精度会以某种方式丢失。 以上代码运行结果为
1.00000001053617 1.00000001053617
1.00000001053617
diffY: 94911150; diffX:94911151 ; a:1.000000
或者你可以自己去 Playground 试试 https://play.golang.org/p/IDS18rfv9e6
谁能解释为什么会这样？以及如何避免这种损失？ 非常感谢。