go - 拆分后如何将数组转换为嵌套的json对象

Question

我正在尝试处理来自 this library 的一些错误描述因为我需要它们是嵌套的 JSON 对象。

错误似乎是一个数组，像这样:

["String length must be greater than or equal to 3","Does not match format 'email'"]

我还需要它来包含包含错误的字段名称:

["Field1: String length must be greater than or equal to 3","Email1: Does not match format 'email'"]

之后，我需要用冒号 : 拆分每个数组值，这样我就可以将字段名称和错误描述放在单独的变量中，例如 slice[0] 和 > slice [1]。

我想像这样制作一个嵌套的 JSON 对象:

{
    "errors": {
        "Field1": "String length must be greater than or equal to 3",
        "Email1": "Does not match format 'email'"
    }
}

这是我尝试实现这一目标的方式:

var errors []string
for _, err := range result.Errors() {
    // Append the errors into an array that we can use to split later
    errors = append(errors, err.Field() + ":" + err.Description())
}

// Make the JSON map we want to append values to
resultMap := map[string]interface{}{
    "errors": map[string]string {
        "Field1": "",
        "Email1": ""
    },
}

// So we actually can use the index keys when appending
resultMapErrors, _ := resultMap["errors"].(map[string]string)

for _, split := range errors {
    slice := strings.Split(split, ":")
    for _, appendToMap := range resultMapErrors {
        appendToMap[slice[0]] = slice[1] // append it like so?
    }
}

finalErrors, _ := json.Marshal(resultMapErrors)
fmt.Println(string(finalErrors))

但这会引发错误

main.go:59:28: non-integer string index slice[0]
main.go:59:39: cannot assign to appendToMap[slice[0]]

有什么线索可以实现吗？

Answer 1

var errors = make(map[string]string)
for _, err := range result.Errors() {
    errors[err.Field()] = err.Description()
}

// Make the JSON map we want to append values to
resultMap := map[string]interface{}{
    "errors": errors,
}

finalErrors, _ := json.Marshal(resultMap)
fmt.Println(string(finalErrors))