我有一个 xml 文件,如下所示:
<?xml version="1.0" encoding="ISO-8859-1" standalone="yes"?>
<HWData xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<NE MOID="WBTS-42" NEType="WBTS">
<EQHO MOID="EQHO-1-0" >
<UNIT MOID="UNIT-FAN-1" State="enabled"></UNIT>
<UNIT MOID="UNIT-FAN-3" State="enabled"></UNIT>
</EQHO>
</NE>
<NE MOID="RNC-40" NEType="RNC">
<EQHO MOID="EQHO-3-0" >
<UNIT MOID="UNIT-FAN-5" State="disabled"></UNIT>
<UNIT MOID="UNIT-FAN-6" State="disabled"></UNIT>
</EQHO>
</NE>
</HWData>
我问如何使用 DOM 获取包含“NE”和“UNIT”标签的 NodeList? 谢谢
最佳答案
您可以手动完成:
import java.io.File;
import java.util.Arrays;
import java.util.HashSet;
import java.util.Set;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import org.w3c.dom.Document;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
public class XmlDomTest {
public static void main(String[] args) throws Exception {
File file = new File("/path/to/your/file");
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(file);
Set<String> filteredNames = new HashSet<String>(Arrays.asList("NE", "UNIT"));
NodeList list = collectNodes(doc, filteredNames);
for (int i = 0; i < list.getLength(); i++)
System.out.println(list.item(i).getNodeName());
}
private static NodeList collectNodes(Document doc, Set<String> filteredNames) {
Node ret = doc.createElement("NodeList");
collectNodes(doc, filteredNames, ret);
return ret.getChildNodes();
}
private static void collectNodes(Node node, Set<String> filteredNames, Node ret) {
NodeList chn = node.getChildNodes();
for (int i = 0; i < chn.getLength(); i++) {
Node child = chn.item(i);
if (filteredNames.contains(child.getNodeName()))
ret.appendChild(child);
collectNodes(child, filteredNames, ret);
}
}
}
关于java - 如何使用DOM选择具有不同标签的节点?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32674559/