我有以下 XML:
<?xml version="1.0" encoding="UTF-8"?>
<details>
...
<address1>Test&Address</address1>
...
</details>
当我尝试使用 JAXB 解码它时,它抛出以下异常:
Caused by: org.xml.sax.SAXParseException: The reference to entity "Address" must end with the ';' delimiter.
at org.apache.xerces.util.ErrorHandlerWrapper.createSAXParseException(Unknown Source)
at org.apache.xerces.util.ErrorHandlerWrapper.fatalError(Unknown Source)
at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source)
at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source)
at org.apache.xerces.impl.XMLScanner.reportFatalError(Unknown Source)
at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl.scanEntityReference(Unknown Source)
at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl$FragmentContentDispatcher.dispatch(Unknown Source)
at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl.scanDocument(Unknown Source)
at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
at org.apache.xerces.parsers.XMLParser.parse(Unknown Source)
at org.apache.xerces.parsers.AbstractSAXParser.parse(Unknown Source)
at org.apache.xerces.jaxp.SAXParserImpl$JAXPSAXParser.parse(Unknown Source)
at com.sun.xml.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal0(UnmarshallerImpl.java:194)
但是当我将 XML 中的 &
更改为 '
时,它起作用了。看起来问题只出在与符号 &
上,我不明白为什么。
要解码的代码是:
JAXBContext context = JAXBContext.newInstance("some.package.name", this.getClass().getClassLoader());
Unmarshaller unmarshaller = context.createUnmarshaller();
obj = unmarshaller.unmarshal(new StringReader(xml));
有人知道吗?
编辑:我尝试了下面@abhin4v 建议的解决方案(即,在 &
之后添加一个空格),但它似乎也不起作用。这是堆栈跟踪:
Caused by: org.xml.sax.SAXParseException: The entity name must immediately follow the '&' in the entity reference.
at org.apache.xerces.util.ErrorHandlerWrapper.createSAXParseException(Unknown Source)
at org.apache.xerces.util.ErrorHandlerWrapper.fatalError(Unknown Source)
at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source)
at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source)
at org.apache.xerces.impl.XMLScanner.reportFatalError(Unknown Source)
at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl.scanEntityReference(Unknown Source)
at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl$FragmentContentDispatcher.dispatch(Unknown Source)
at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl.scanDocument(Unknown Source)
at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
at org.apache.xerces.parsers.XMLParser.parse(Unknown Source)
at org.apache.xerces.parsers.AbstractSAXParser.parse(Unknown Source)
at org.apache.xerces.jaxp.SAXParserImpl$JAXPSAXParser.parse(Unknown Source)
at com.sun.xml.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal0(UnmarshallerImpl.java:194)
最佳答案
我也遇到过。首先,我只是将 & 替换为标记字符串 (AMPERSAND_TOKEN),通过 JAXB 发送它,然后重新替换 & 符号。不理想,但这是一个快速修复。
第二遍我做了很多重要的改变,所以我不确定究竟是什么解决了问题。我怀疑提供对 html dtds 的 JAXB 访问会让它更快乐,但这只是一个猜测,可能特定于我的项目。
HTH
关于Java XML 解码在使用 JAXB 的符号 (&) 上失败,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2999132/