我正在尝试从 servlet 获取 XML 响应。 servlet 返回内容类型“application/xml”。使用 XmlHttpRequest，我可以获得 responseText，但不是 responseXml。我想知道这是否与内容类型或请求类型有关(我正在执行 GET)...？
非常感谢!
我已经精简了所有文件。我认为我设置正确。这是我拥有的:
-------- HTML ------
<html>
<head>
<title></title>
<script src="js/jboard_simple.js" type="text/javascript"> </script>
</head>
<body>
<div id="myDiv">
<h2>No results yet....</h2>
</div>
<form name="searchForm" id="searchForm_id">
<input type="text" name="searchString" id="searchString_id" />
<button type="button" onclick="loadXMLDoc()">Perform Search</button>
</form>
</body>
</html>
-------- JavaScript ------------
function loadXMLDoc() {
document.getElementById("myDiv").innerHTML = "searching...";
var xmlhttp;
if (window.XMLHttpRequest) {
xmlhttp = new XMLHttpRequest();
} else {
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
// Do something here...
alert(xmlhttp.responseText);
alert(xmlhttp.responseXml);
processSearchServletResponse(xmlhttp.responseText);
}
}
// Find teh search string
var searchString_el = window.document.getElementById('searchString_id');
var searchString = searchString_el.value;
alert('searchString: ' + searchString);
var searchUrl = "/SimpleServlet?searchString=" + searchString;
xmlhttp.open("GET", searchUrl, true);
xmlhttp.send();
}
function processSearchServletResponse(xmlTxt) {
document.getElementById("myDiv").innerHTML = xmlTxt;
}
-------- 小服务程序 --------
import java.io.BufferedOutputStream;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.log4j.Logger;
import org.apache.log4j.LogManager;
public class SimpleServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
private static Logger logger = LogManager.getRootLogger();
public void service(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException {
BufferedOutputStream bs = null;
String simpleResponse = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><root>hi</root>";
try {
res.setContentType("text/xml");
res.setCharacterEncoding("UTF-8");
bs = new BufferedOutputStream(res.getOutputStream());
bs.write(simpleResponse.getBytes());
} catch (Exception ex) {
logger.error("JboardSearchServlet.service(): error = ", ex);
} finally {
bs.flush();
bs.close();
}
}
}
最佳答案
亲爱的!我刚刚弄清楚了我的整个问题(在别人看过之后)。
我使用的是“responseXml”而不是“responseXML”。该死的大写字母 =)
关于javascript - application/xml 与 text/xml 内容类型，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/6657787/