如何在 xsd 中定义一个子元素有父元素的元素？
这是一个例子:
<score seq="1" type="test" numeric="23">
<option lbound="0" ubound="">
<score seq="1" type="app" numeric="575">
<option lbound="" ubound="0">0</option>
</score>
</option>
</score>
最佳答案
像这样:
<?xml version="1.0" encoding="utf-8"?>
<xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:element name="score">
<xs:complexType>
<xs:sequence>
<xs:element name="option">
<xs:complexType>
<xs:sequence>
<xs:element name="score">
<xs:complexType>
<xs:sequence>
<xs:element name="option">
<xs:complexType>
<xs:simpleContent>
<xs:extension base="xs:unsignedByte">
<xs:attribute name="lbound" type="xs:string" use="required" />
<xs:attribute name="ubound" type="xs:unsignedByte" use="required" />
</xs:extension>
</xs:simpleContent>
</xs:complexType>
</xs:element>
</xs:sequence>
<xs:attribute name="seq" type="xs:unsignedByte" use="required" />
<xs:attribute name="type" type="xs:string" use="required" />
<xs:attribute name="numeric" type="xs:unsignedShort" use="required" />
</xs:complexType>
</xs:element>
</xs:sequence>
<xs:attribute name="lbound" type="xs:unsignedByte" use="required" />
<xs:attribute name="ubound" type="xs:string" use="required" />
</xs:complexType>
</xs:element>
</xs:sequence>
<xs:attribute name="seq" type="xs:unsignedByte" use="required" />
<xs:attribute name="type" type="xs:string" use="required" />
<xs:attribute name="numeric" type="xs:unsignedByte" use="required" />
</xs:complexType>
</xs:element>
</xs:schema>
关于xml - 如何在 xsd 中定义一个元素，该元素在子元素中具有父元素，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/13927688/