xml - 如何使用 XQUERY 在 T-SQL 中获取给定 XML 属性的许多元素？

Question

我想知道如何获取其中所有具有属性 TIPO 且等于“MC”的元素

XML 是:

<ROOT>
  <PARAMETERS>
    <USU_LOGIN>yleon</USU_LOGIN>
    <USU_NOMBREPRIMERO>Yerusha</USU_NOMBREPRIMERO>
    <USU_APELLIDOPRIMERO>Leon</USU_APELLIDOPRIMERO>
    <USU_EMAIL>yleon@pt.com.ve</USU_EMAIL>
    <USU_FECHACREACION>201305270</USU_FECHACREACION>
    <USU_CONDITIONS1 TIPO="MC">AND USU_ID=4</USU_CONDITIONS1>
    <USU_CONDITIONS2 TIPO="MC">AND USU_ID=5</USU_CONDITIONS2>
    <USU_CONDITIONS3 TIPO="ZZ">AND USU_ID=9</USU_CONDITIONS3>
  </PARAMETERS>
</ROOT>

预期的结果是:

AND USU_ID=4
AND USU_ID=5

Answer 1

检查这个:

DECLARE @xml XML
SET @xml = '<ROOT>
  <PARAMETERS>
    <USU_LOGIN>yleon</USU_LOGIN>
    <USU_NOMBREPRIMERO>Yerusha</USU_NOMBREPRIMERO>
    <USU_APELLIDOPRIMERO>Leon</USU_APELLIDOPRIMERO>
    <USU_EMAIL>yleon@pt.com.ve</USU_EMAIL>
    <USU_FECHACREACION>201305270</USU_FECHACREACION>
    <USU_CONDITIONS1 TIPO="MC">AND USU_ID=4</USU_CONDITIONS1>
    <USU_CONDITIONS2 TIPO="MC">AND USU_ID=5</USU_CONDITIONS2>
    <USU_CONDITIONS3 TIPO="ZZ">AND USU_ID=9</USU_CONDITIONS3>
  </PARAMETERS>
</ROOT>'


-- RESULTS
SELECT txt = T.Item.value('data(.)', 'varchar(255)')
FROM   @xml.nodes('//PARAMETERS/*') AS T(Item)
WHERE T.Item.value('data(@TIPO)', 'varchar(255)')='MC'


-- output
AND USU_ID=4
AND USU_ID=5