因为一个标签由数字组成,每次我想阅读它时都会发生变化,但这段代码不起作用,我在 StrMyXml.nodeName(无效标识符)处收到错误。 目前我的代码是这样的:
Sub Create_XSD()
Dim StrMyXml As String, MyMap As XmlMap
Dim StrMySchema As String
Dim tempString As String
StrMyXml = "<Translate>"
StrMyXml = StrMyXml & "<Alarms>"
tempString = StrMyXml.nodeName
StrMyXml = StrMyXml & "<" & tempString & ">"
StrMyXml = StrMyXml & "<Nummer>tempString</Nummer>"
StrMyXml = StrMyXml & "<Nummer Diagnosename DE>tempString & Text</Nummer Diagnosename DE>"
StrMyXml = StrMyXml & "<Nummer Diagnosename EN>tempString & Text</Nummer Diagnosename EN>"
StrMyXml = StrMyXml & "</" & tempString & ">"
StrMyXml = StrMyXml & "</Alarms>"
StrMyXml = StrMyXml & "<Alarms></Alarms>"
StrMyXml = StrMyXml & "</Translate>"
' Turn off async loading.
Application.DisplayAlerts = False
' Add the string to the XmlMaps collection.
Set MyMap = ThisWorkbook.XmlMaps.Add(StrMyXml)
Application.DisplayAlerts = True
' Create an empty file and output the schema.
StrMySchema = ThisWorkbook.XmlMaps(1).Schemas(1).XML
Open "D:\Users\F512\Desktop\MySchema.xsd" For Output As #1
Print #1, StrMySchema
Close #1
End Sub
感谢您的帮助!
劳伦斯
最佳答案
您已将 StrMyXml 标注为字符串:
将 StrMyXml 调暗为字符串
然后你尝试:
tempString = StrMyXml.nodeName
这不起作用,因为字符串没有这样的属性。
关于xml - 获取一个xml文件的标签名,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25507597/