我正在使用下面的 XML
<Root>
<sample>1</sample>
<sample>2</sample>
<sample>3</sample>
<sample>4</sample>
<sample>5</sample>
<sample>6</sample>
</Root>
我想得到下面给出的输出
<sample>123456</sample>
我正在使用下面的 XSLT 来获得上面的输出。但我得到的输出是这样的。
<sample>1</sample>
<sample>23456</sample>
<sample>2</sample>
<sample>3456</sample>
<sample>3</sample>
<sample>456</sample>
<sample>4</sample>
<sample>56</sample>
<sample>5</sample>
<sample>6</sample
><sample>6</sample>
<sample></sample>
这是我试过的 XSL 代码:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="sample">
<presample>
<xsl:value-of select="."/>
<xsl:variable name="code" select="following-sibling::sample" />
<xsl:for-each select="following-sibling::sample">
<xsl:if test="not(preceding-sibling::sample)">
<xsl:value-of select="."/>
</xsl:if>
</xsl:for-each>
</presample>
</xsl:template>
</xsl:stylesheet>
请帮助我更正此 XSLT 以获得上述所需的输出。
最佳答案
怎么样:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="sample[1]">
<sample>
<xsl:for-each select=". | following-sibling::sample">
<xsl:value-of select="."/>
</xsl:for-each>
</sample>
</xsl:template>
<xsl:template match="sample[position() > 1]" />
</xsl:stylesheet>
我想您的最终目标比这更复杂一些,所以如果您能详细说明,可能会有更好的通用方法。
不确定这是否是您想要的,但这里有一个可能更通用的方法:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="*[text()[normalize-space(.)] and not(name(preceding-sibling::*[1]) = name())]">
<xsl:copy>
<xsl:variable name="list" select=". | following-sibling::*"/>
<xsl:for-each select="$list">
<xsl:variable name="pos" select="position()" />
<xsl:if test="not($list[position() < $pos and name() != name(current())])">
<xsl:value-of select="."/>
</xsl:if>
</xsl:for-each>
</xsl:copy>
</xsl:template>
<xsl:template match="*[name(preceding-sibling::*[1]) = name()]" />
<xsl:template match="text()" />
</xsl:stylesheet>
在此运行时:
<Root>
<sample>1</sample>
<sample>2</sample>
<sample>3</sample>
<sample>4</sample>
<sample>5</sample>
<sample>6</sample>
<child>
<something>4</something>
<something>5</something>
<something>6</something>
<something>7</something>
<somethingelse>a</somethingelse>
<somethingelse>b</somethingelse>
<somethingelse>c</somethingelse>
<somethingelse>d</somethingelse>
<something>8</something>
<something>9</something>
<something>10</something>
</child>
</Root>
产生这个:
<sample>123456</sample>
<something>4567</something>
<somethingelse>abcd</somethingelse>
<something>8910</something>
关于xml - 使用 XSLT 对 XML 中相似节点的内容进行分组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14272908/