我正在使用 C# 中的天气 Web 服务。我正在传递它的 Lat-Long 并返回该区域的预测最高和最低温度。以下是我正在使用的代码
var response = client.ndfdGen(latlong);
XmlDocument doc = new XmlDocument();
doc.LoadXml(response);
以下是我得到的响应数据，即 xml response
在这个响应中，有纬度和经度。 我必须提取这个。
<SOAP-ENV:Envelope SOAP-ENV:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:SOAP-ENC="http://schemas.xmlsoap.org/soap/encoding/">
<SOAP-ENV:Body>
<ns1:NDFDgenResponse xmlns:ns1="http://graphical.weather.gov/xml/DWMLgen/wsdl/ndfdXML.wsdl">
<dwmlOut xsi:type="xsd:string"><![CDATA[<?xml version="1.0"?>
<dwml version="1.0" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="http://www.nws.noaa.gov/forecasts/xml/DWMLgen/schema/DWML.xsd">
<head>
<product srsName="WGS 1984" concise-name="time-series" operational-mode="official">
<title>NOAA's National Weather Service Forecast Data</title>
<field>meteorological</field>
<category>forecast</category>
<creation-date refresh-frequency="PT1H">2015-04-15T15:13:07Z</creation-date>
</product>
<source>
<more-information>http://www.nws.noaa.gov/forecasts/xml/</more-information>
<production-center>Meteorological Development Laboratory<sub-center>Product Generation Branch</sub-center></production-center>
<disclaimer>http://www.nws.noaa.gov/disclaimer.html</disclaimer>
<credit>http://www.weather.gov/</credit>
<credit-logo>http://www.weather.gov/images/xml_logo.gif</credit-logo>
<feedback>http://www.weather.gov/feedback.php</feedback>
</source>
</head>
<data>
<location>
<location-key>point1</location-key>
<point latitude="39.01" longitude="-77.02"/>
</location>
<moreWeatherInformation applicable-location="point1">http://forecast.weather.gov/MapClick.php?textField1=39.01&textField2=-77.02</moreWeatherInformation>
<time-layout time-coordinate="local" summarization="none">
<layout-key>k-p24h-n2-1</layout-key>
<start-valid-time>2015-04-17T08:00:00-04:00</start-valid-time>
<end-valid-time>2015-04-17T20:00:00-04:00</end-valid-time>
<start-valid-time>2015-04-18T08:00:00-04:00</start-valid-time>
<end-valid-time>2015-04-18T20:00:00-04:00</end-valid-time>
</time-layout>
<parameters applicable-location="point1">
<temperature type="maximum" units="Fahrenheit" time-layout="k-p24h-n2-1">
<name>Daily Maximum Temperature</name>
<value>68</value>
<value>71</value>
</temperature>
</parameters>
</data>
</dwml>]]></dwmlOut>
</ns1:NDFDgenResponse>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>
我想提取<time-layout time-coordinate="local" summarization="none">中的信息喜欢start-valid-time , end-valid-time和 temperature来自 <temperature type="maximum" units="Fahrenheit" time-layout="k-p24h-n2-1">标签。
我怎样才能接触到这些节点并对其进行迭代？
最佳答案
您必须首先提取 CDATA，这确实是这里唯一的特殊挑战 - 然后您可以使用 XmlDocument 或 XDocument 或 XmlReader。我建议这样做:
var response = client.ndfdGen(latlong);
XDocument xd = null;
using (XmlReader xr = XmlReader.Create(new StringReader(response))) // load the response into an XmlReader
{
xr.ReadToDescendant("dwmlOut"); // go to the dwmlOut node
xr.Read(); // move to the CDATA in that node
xd = XDocument.Parse(xr.Value); // load **that** XML into your XDocument
}
string startTime = xd.Descendants("start-valid-time").First().Value;
等等。
如果你坚持使用 XmlDocument，你可以在这里使用相同的方法，只需执行 XmlDocument.LoadFrom(xr.Value)，但 XDocument API 更灵活一些，性能肯定会更好.
关于c# - 使用 XmlDocument 从 XML 中提取数据，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/29654218/