您好,我有 2 个 xml 节点,我只需要将所有属性从第一个复制到另一个 `
XmlDocument doc = new XmlDocument();
XmlDocument doc1 = new XmlDocument();
doc.Load(somepath);
XmlNode node=doc.CreateNode(System.Xml.XmlNodeType.Element, "something", null);
System.Xml.XmlNodeList list = doc.GetElementsByTagName("tananana");
XmlNode node1= list[0];
Foreach (XmlAttribute att in node1.Attributes)
{
System.Xml.XmlAttribute rAtt= doc.CreateAttribute(att.name ); //att.name is problem
rAtt.Value=att.Value; //att.value is problem
node1.Attributes.Add(rAtt);
}
输入test.xml:
<data>
<tananana a1="1" a2="2"/>
<tananana a3="3" a4="5"/>
<tananana a1="5" a2="7"/>
</data>
输出:
<data>
<something a1="1" a2="2" />
<something a3="3" a4="5" />
<something a1="5" a2="7" />
</data>
最佳答案
输入test.xml:
<data>
<tananana a1="1" a2="2"/>
<tananana a3="3" a4="5"/>
<tananana a1="5" a2="7"/>
</data>
输出:
<data>
<something a1="1" a2="2" />
<something a3="3" a4="5" />
<something a1="5" a2="7" />
</data>
代码:
namespace StackOverflow
{
using System.IO;
using System.Linq;
using System.Xml.Linq;
class Program
{
static void Main(string[] args)
{
var doc1 = XDocument.Load("test.xml");
var doc2 = new XDocument(new XElement(doc1.Root.Name));
doc2.Root.Add(doc1.Root
.Elements("tananana")
.Select(x => new XElement("something", x.Attributes())));
}
}
}
关于c# - 将所有 xml 属性从一个节点复制到另一个节点,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43610202/