我有一个 XML 文件,由用 C++ 编写的库生成:
<?xml version="1.0" encoding="UTF-8" ?>
<main>
<days>
<day>
<date>27.06.2014</date>
<p/>
</day>
<day>
<date>28.06.2014</date>
<p>
<short>short value</short>
<name>name value</name>
<type>type value</type>
<aud>aud value</aud>
<tr>tr value</tr>
<added>added value</added>
</p>
<p>
<short>short value</short>
<name>name value</name>
<type>type value</type>
<aud>aud value</aud>
<tr>tr value</tr>
<added>added value</added>
</p>
</day>
...
</days>
<di>
<did>
<dayname>Пн</dayname>
<sw>1</sw>
<st>8:00-9:35</st>
</did>
<did>
<dayname>Вт</dayname>
<sw>2</sw>
<st>9:45-11:20</st>
</did>
...
</di>
</main>
我读取这些 xml 文件如下:
XmlTextReader r = new XmlTextReader("out.xml");
while (r.Read())
{
if (r.Name == "date") { r.Read(); dates[c1] = (r.Value); c1++; }
else if (r.Name == "short") { r.Read(); shorts[c2] = (r.Value); c2++; }
else if (r.Name == "name") { r.Read(); names[c3] = (r.Value); c3++; }
else if (r.Name == "type") { r.Read(); types[c4] = (r.Value); c4++; }
else if (r.Name == "aud") { r.Read(); auds[c5] = (r.Value); c5++; }
else if (r.Name == "tr") { r.Read(); trs[c6] = (r.Value); c6++; }
else if (r.Name == "sw") { r.Read(); ws[c7] = (r.Value); c7++; }
else if (r.Name == "st") { r.Read(); st[c8] = (r.Value); c8++; }
}
r.Close();
我如何解析文件,以便我可以理解哪一天属于哪个参数,尤其是一天中有多个参数(在本例中为“p”)?在网上找了解决办法,很多人说用“LINQ to XML”或者“XPath”比较好,但是没有人说如何维护对象依赖。
最佳答案
使用 XDocument 类加载您的 xml,然后您可以使用 Descendants 或 Element 方法遍历它。
var xml = XDocument.Load("your xml string");
foreach (var day in xml.Descendants("day"))
{
var pChildren = day.Descendants("p").ToList();
var aretThereMorePs = pChildren.Count() > 1;
foreach (var p in pChildren)
{
var shortVal = (string)p.Element("short");
//etc
}
}
关于c# - 在 C# 中解析 XML 文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/24456903/