我需要将一些对象存储为 XML 文件，以便保存数据并在以后加载它。
我对此进行了编码，它对我有用:
public static Project Load(String file)
{
using (var stream = System.IO.File.OpenRead(file))
{
var serializer = new XmlSerializer(typeof(Project));
return serializer.Deserialize(stream) as Project;
}
}
public static void Save(Project p, String file)
{
using (var writer = new System.IO.StreamWriter(file))
{
var serializer = new XmlSerializer(p.GetType());
serializer.Serialize(writer, p);
writer.Flush();
}
}
现在，我需要对其他类型的对象执行此操作，我真的不想为每个对象类复制/粘贴这些方法。
是否可以将对象类传递给方法并使这些方法对任何对象类都是通用的？
我通常使用 https://stackoverflow.com/a/271423/1315444 中的这两种方法
希望这有帮助 :D
/// <summary>Serializes an object of type T in to an xml string</summary>
/// <typeparam name="T">Any class type</typeparam>
/// <param name="obj">Object to serialize</param>
/// <returns>A string that represents Xml, empty otherwise</returns>
public static string XmlSerialize<T>(this T obj) where T : class, new()
{
if (obj == null) throw new ArgumentNullException("obj");
var serializer = new XmlSerializer(typeof(T));
using (var writer = new StringWriter())
{
serializer.Serialize(writer, obj);
return writer.ToString();
}
}
/// <summary>Deserializes an xml string in to an object of Type T</summary>
/// <typeparam name="T">Any class type</typeparam>
/// <param name="xml">Xml as string to deserialize from</param>
/// <returns>A new object of type T is successful, null if failed</returns>
public static T XmlDeserialize<T>(this string xml) where T : class, new()
{
if (xml == null) throw new ArgumentNullException("xml");
var serializer = new XmlSerializer(typeof(T));
using (var reader = new StringReader(xml))
{
try { return (T)serializer.Deserialize(reader); }
catch { return null; } // Could not be deserialized to this type.
}
}
然后你可以去
Project p = new Project();
string result = p.XmlSerialize();
Project p2 = result.XmlDeserialize<Project>();