xml - 尝试使用 XDT 和 XPath 定位器替换 XML 元素元素

Question

您好，我正在尝试更换 <cron-expression>通过在 quartz.net 作业描述文件上使用以下转换来使用 VS2012 XDT。我已经使用在线测试仪测试了 XPath 定位器，它返回“我认为我需要的”。感谢您的帮助。

<schedule>
    <trigger>
        <cron xdt:Locator="XPath(//job-scheduling-data/schedule/trigger/cron[name='crontriggername2'])" >
            <cron-expression  xdt:Transform="Replace">***some data***</cron-expression>
        </cron>
    </trigger>
</schedule>

示例 XML 文件 (Quartz.net)

  <job-scheduling-data xmlns="http://quartznet.sourceforge.net/JobSchedulingData" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.0"><processing-directives>
    <overwrite-existing-data>true</overwrite-existing-data>
</processing-directives>

<schedule>
       <trigger>
        <cron>
            <name>crontriggername1</name>
            <group>crontriggergroup1</group>
            <description>crontriggerdesc1</description>
            <job-name>crontriggerjobname1</job-name>
            <job-group>crontriggerjgroup1</job-group>
            <misfire-instruction>crontriggermisfile1</misfire-instruction>
            <cron-expression>0/5 * * * * ?</cron-expression>
        </cron>
    </trigger>

    <trigger>
        <cron>
            <name>crontriggername2</name>
            <group>crontriggergroup2</group>
            <description>crontriggerdesc2</description>
            <job-name>crontriggerjobname2</job-name>
            <job-group>crontriggerjgroup2</job-group>
            <misfire-instruction>crontriggermisfile2</misfire-instruction>
            <cron-expression>0/13 * * * * ?</cron-expression>
        </cron>
    </trigger>      
</schedule>

XPath //job-scheduling-data/schedule/trigger/cron[name='crontriggername2']

返回正确的元素组 ( http://www.freeformatter.com/xpath-tester.html 1 )

<cron>
  <name>crontriggername2</name>
  <group>crontriggergroup2</group>
  <description>crontriggerdesc2</description>
  <job-name>crontriggerjobname2</job-name>
  <job-group>crontriggerjgroup2</job-group>
  <misfire-instruction>crontriggermisfile2</misfire-instruction>
  <cron-expression>0/13 * * * * ?</cron-expression>
</cron>

我的表达式基于 Log4net 上另一个 XDT 问题的解决方案 (log4Net config transform)

谁能指出我正确的解决方案，这让我发疯。提前致谢。

Answer 1

另一种不需要对原始文件进行任何修改的解决方案是

<job-scheduling-data xmlns="http://quartznet.sourceforge.net/JobSchedulingData" xmlns:xdt="http://schemas.microsoft.com/XML-Document-Transform">
<schedule>
    <trigger>


        <cron xdt:Locator="XPath(//*[local-name()='job-scheduling-data']
                                 /*[local-name()='schedule']
                                 /*[local-name()='trigger']
                                 /*[local-name()='cron']
                                   [*[local-name() = 'name'] = 'MyTriggerName'])">

or this syntax...

        <cron xdt:Locator="XPath(//*[local-name()='job-scheduling-data' and namespace-uri()='http://quartznet.sourceforge.net/JobSchedulingData']
                                 /*[local-name()='schedule' and namespace-uri()='http://quartznet.sourceforge.net/JobSchedulingData']
                                 /*[local-name()='trigger' and namespace-uri()='http://quartznet.sourceforge.net/JobSchedulingData']
                                 /*[local-name()='cron' and namespace-uri()='http://quartznet.sourceforge.net/JobSchedulingData']
                                   [*[local-name() = 'name'] = 'MyTriggerName'])">

            <cron-expression  xdt:Transform="Replace">***some data***</cron-expression>
        </cron>
    </trigger>
</schedule>

另见 I am trying to get the Xpath for a value but getting error for nested condition