我有下面的输入 XML,需要使用 xslt 进行转换
输入 Xml:
<result>
<circuit>MX123456</circuit>
<psaresult>
<Live_Alarms>
<diagnosis>
<utr>xxx</utr>
<dtr>xxx</dtr>
<text />
<site>xxx</site>
<address />
<tech_type />
<end />
<network_type>xxx</network_type>
</diagnosis>
<Alarms>
<alarmId>463</alarmId>
<cct>xxx</cct>
<eventTime>12/05/11 09:21:21</eventTime>
<clearTime />
<problemCode>xxxx</problemCode>
<problemText>xxxx</problemText>
<equipmentName>xxx</equipmentName>
<unit>xxx</unit>
<rcKey>xxx</rcKey>
<category>xxx</category>
<rootCause>xxxx</rootCause>
</Alarms>
<Alarms>
<alarmId>464</alarmId>
<cct>xxx</cct>
<eventTime>12/05/11 09:21:22</eventTime>
<clearTime />
<problemCode>yyyy</problemCode>
<problemText>yyyy</problemText>
<equipmentName>yyyy</equipmentName>
<unit>yyyy</unit>
<rcKey>yyyy</rcKey>
<category>yyyy</category>
<rootCause>yyyy</rootCause>
</Alarms>
</Live_Alarms>
</psaresult>
</result>
预期输出:
<result>
<circuit>MX123456</circuit>
<psaresult>
<Live_Alarms>
<psadiagnosis>
<utr>xxx</utr>
<dtr>xxx</dtr>
<text />
<site>xxx</site>
<address />
<tech_type />
<end />
<network_type>xxx</network_type>
</psadiagnosis>
<Alarms>
<alarmId>463</alarmId>
<cct>xxx</cct>
<eventTime>12/05/11 09:21:21</eventTime>
<clearTime />
<problemCode>xxxx</problemCode>
<problemText>xxxx</problemText>
<equipmentName>xxx</equipmentName>
<unit>xxx</unit>
<rcKey>xxx</rcKey>
<category>xxx</category>
<rootCause>xxxx</rootCause>
</Alarms>
</Live_Alarms>
</psaresult>
</result>
注意:只需要第一个 Alarms
节点,就像 SelectSinglenode
所做的那样,所有其他节点都需要从输出中截断。您能否建议如何通过 xslt 实现这一点?
最佳答案
这是基于规范身份规则的解决方案:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Alarms[position() >1]"/>
</xsl:stylesheet>
应用于提供的 XML 文档时:
<result>
<circuit>MX123456</circuit>
<psaresult>
<Live_Alarms>
<diagnosis>
<utr>xxx</utr>
<dtr>xxx</dtr>
<text />
<site>xxx</site>
<address />
<tech_type />
<end />
<network_type>xxx</network_type>
</diagnosis>
<Alarms>
<alarmId>463</alarmId>
<cct>xxx</cct>
<eventTime>12/05/11 09:21:21</eventTime>
<clearTime />
<problemCode>xxxx</problemCode>
<problemText>xxxx</problemText>
<equipmentName>xxx</equipmentName>
<unit>xxx</unit>
<rcKey>xxx</rcKey>
<category>xxx</category>
<rootCause>xxxx</rootCause>
</Alarms>
<Alarms>
<alarmId>464</alarmId>
<cct>xxx</cct>
<eventTime>12/05/11 09:21:22</eventTime>
<clearTime />
<problemCode>yyyy</problemCode>
<problemText>yyyy</problemText>
<equipmentName>yyyy</equipmentName>
<unit>yyyy</unit>
<rcKey>yyyy</rcKey>
<category>yyyy</category>
<rootCause>yyyy</rootCause>
</Alarms>
</Live_Alarms>
</psaresult>
</result>
产生了完全想要的、正确的结果:
<result>
<circuit>MX123456</circuit>
<psaresult>
<Live_Alarms>
<diagnosis>
<utr>xxx</utr>
<dtr>xxx</dtr>
<text/>
<site>xxx</site>
<address/>
<tech_type/>
<end/>
<network_type>xxx</network_type>
</diagnosis>
<Alarms>
<alarmId>463</alarmId>
<cct>xxx</cct>
<eventTime>12/05/11 09:21:21</eventTime>
<clearTime/>
<problemCode>xxxx</problemCode>
<problemText>xxxx</problemText>
<equipmentName>xxx</equipmentName>
<unit>xxx</unit>
<rcKey>xxx</rcKey>
<category>xxx</category>
<rootCause>xxxx</rootCause>
</Alarms>
</Live_Alarms>
</psaresult>
</result>
解释:
identity rule (模板)“按原样”复制每个节点。
有一个模板覆盖身份规则。它匹配任何不是其父元素的第一个
Alarms
子元素的Alarms
元素。此模板没有正文——有效地丢弃了任何此类匹配元素,以免被复制到输出中。
关于xml - XSLT:根据名称属性删除重复节点,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6734138/