我对此束手无策,想知道这是否可以通过 XSL 实现。假设我有这个 XML 数据:
<?xml version="1.0" standalone="yes"?>
<Data>
<Row>
<F1>Created By</F1>
<F2>City</F2>
</Row>
<Row>
<F1>John Doe</F1>
<F2>Los Angeles</F2>
</Row>
<Row>
<F1>Jane Doe</F1>
<F2>San Diego</F2>
</Row>
</Data>
我想在遍历其余数据时重复第一行元素。简而言之,我希望输出为:
[Created By] [City]
----------- ------------
[John Doe] [Los Angeles]
[Created By] [City]
---------- ------------
[Jane Doe] [San Diego]
什么是最好的方法?我尝试将第一个元素“Created By”设置为变量,但当我尝试使用它时它没有呈现。我是 XSL 的新手,我们将不胜感激。
谢谢
最佳答案
这是一个解决方案,与当前接受的答案不同,它正确处理具有各种预先未知长度的数据——进一步查看处理无限数量列的更新,也是:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:variable name="vMax1">
<xsl:call-template name="maxLength">
<xsl:with-param name="pNodes" select="/*/*/*[1]"/>
</xsl:call-template>
</xsl:variable>
<xsl:variable name="vMax2">
<xsl:call-template name="maxLength">
<xsl:with-param name="pNodes" select="/*/*/*[2]"/>
</xsl:call-template>
</xsl:variable>
<xsl:variable name="vLongest1" select=
"/*/*/*[1][string-length() = $vMax1][1]"/>
<xsl:variable name="vLongest2" select=
"/*/*/*[2][string-length() = $vMax2][1]"/>
<xsl:variable name="vUnderscores1" select=
"concat('__',
translate($vLongest1,translate($vLongest1, '_', ''),
'_________________________________________________________')
)"/>
<xsl:variable name="vUnderscores2" select=
"concat('__',
translate($vLongest2,translate($vLongest2, '_', ''),
'_________________________________________________________')
)"/>
<xsl:variable name="vBlanks1"
select="translate($vUnderscores1,'_', ' ')"/>
<xsl:variable name="vBlanks2"
select="translate($vUnderscores2,'_', ' ')"/>
<xsl:variable name="vTitle1" select=
"concat('[',/*/*/*[1],']',
substring($vBlanks1,1,
string-length($vBlanks1)-string-length(/*/*/*[1]))
)"/>
<xsl:variable name="vTitle2" select=
"concat('[',/*/*/*[2],']',
substring($vBlanks2,1,
string-length($vBlanks2)-string-length(/*/*/*[2]))
)"/>
<xsl:template match="Row">
<xsl:value-of select=
"concat('
', $vTitle1, $vTitle2)"/>
<xsl:value-of select=
"concat('
',$vUnderscores1, ' ', $vUnderscores2, '
')"/>
<xsl:value-of select=
"concat(F1,
substring($vBlanks1,1,
string-length($vBlanks1)-string-length(F1)),
' ',
F2,
substring($vBlanks1,1,
string-length($vBlanks1)-string-length(F2)),
'
'
)"/>
</xsl:template>
<xsl:template name="maxLength">
<xsl:param name="pNodes" select="/.."/>
<xsl:for-each select="$pNodes">
<xsl:sort select="string-length()"
data-type="number" order="descending"/>
<xsl:if test="position() = 1">
<xsl:value-of select="string-length()"/>
</xsl:if>
</xsl:for-each>
</xsl:template>
<xsl:template match="Row[1]|text()"/>
</xsl:stylesheet>
当此转换应用于提供的 XML 文档时:
<Data>
<Row>
<F1>Created By</F1>
<F2>City</F2>
</Row>
<Row>
<F1>John Doe</F1>
<F2>Los Angeles</F2>
</Row>
<Row>
<F1>Jane Doe</F1>
<F2>San Diego</F2>
</Row>
</Data>
产生了想要的、正确的结果:
[Created By] [City]
____________ _____________
John Doe Los Angeles
[Created By] [City]
____________ _____________
Jane Doe San Diego
更有趣的是,当应用于此 XML 文档时:
<Data>
<Row>
<F1>Created By</F1>
<F2>City</F2>
</Row>
<Row>
<F1>John Doe</F1>
<F2>La Villa Real de la Santa Fe de San Francisco de Asis</F2>
</Row>
<Row>
<F1>Josiah Willard Gibbs</F1>
<F2>San Diego</F2>
</Row>
</Data>
再次产生正确的结果:
[Created By] [City]
______________________ _______________________________________________________
John Doe La Villa Real de la Santa Fe de San Francisco de Asis
[Created By] [City]
______________________ _______________________________________________________
Josiah Willard Gibbs San Diego
将此正确结果与当前接受的答案产生的结果进行比较:
Created By City
----------- -----------
John Doe La Villa Real de la Santa Fe de San Francisco de Asis
Created By City
----------- -----------
Josiah Willard GibbsSan Diego
II 同一解决方案的 XSLT 2.0 变体:更短且更易于编写:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xsl:output method="text"/>
<xsl:variable name="vMax" as="xs:integer*" select=
"for $i in 1 to 2
return
max(/*/*/*[$i]/string-length(.))"/>
<xsl:variable name="vUnderscores" select=
"for $i in 1 to 2
return
concat('__',
string-join((for $len in 1 to $vMax[$i]
return '_'), '')
)"/>
<xsl:variable name="vBlanks" select=
"for $i in 1 to 2
return
translate($vUnderscores[$i],'_', ' ')
"/>
<xsl:variable name="vTitle" select=
"for $i in 1 to 2
return
concat('[',(*/*/*)[$i],']',
substring($vBlanks[$i],1,
$vMax[$i]+2 -string-length((/*/*/*)[$i]))
)
"/>
<xsl:template match="Row">
<xsl:value-of select=
"concat('
', $vTitle[1], $vTitle[2])"/>
<xsl:value-of select=
"concat('
',$vUnderscores[1], ' ', $vUnderscores[2], '
')"/>
<xsl:value-of select=
"concat(F1,
substring($vBlanks[1],1,
$vMax[1]+2 -string-length(F1)),
' ',
F2,
substring($vBlanks[2],1,
$vMax[1]+2 -string-length(F2)),
'
'
)"/>
</xsl:template>
<xsl:template match="Row[1]|text()"/>
</xsl:stylesheet>
III.处理不确定数量的列:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xsl:output method="text"/>
<xsl:variable name="vNumCols" select="max(/*/*/count(*))"/>
<xsl:variable name="vMax" as="xs:integer*" select=
"for $i in 1 to $vNumCols
return
max(/*/*/*[$i]/string-length(.))"/>
<xsl:variable name="vUnderscores" select=
"for $i in 1 to $vNumCols
return
concat('__',
string-join((for $len in 1 to $vMax[$i]
return '_'), '')
)"/>
<xsl:variable name="vBlanks" select=
"for $i in 1 to $vNumCols
return
translate($vUnderscores[$i],'_', ' ')
"/>
<xsl:variable name="vTitle" select=
"for $i in 1 to $vNumCols
return
concat('[',(*/*/*)[$i],']',
substring($vBlanks[$i],1,
$vMax[$i]+2 -string-length((/*/*/*)[$i]))
)
"/>
<xsl:template match="Row">
<xsl:value-of separator="" select=
"'
', string-join($vTitle, '')"/>
<xsl:value-of separator="" select=
"'
', string-join($vUnderscores, ' '), '
'"/>
<xsl:value-of select=
"string-join((for $i in 1 to $vNumCols,
$vChild in *[$i]
return
($vChild,
substring($vBlanks[$i],1,
$vMax[$i]+2 -string-length($vChild)
),
' '
),
'
'
),
''
)"/>
</xsl:template>
<xsl:template match="Row[1]|text()"/>
</xsl:stylesheet>
应用于此 XML 文档时(3 列):
<Data>
<Row>
<F1>Created By</F1>
<F2>City</F2>
<F3>Region</F3>
</Row>
<Row>
<F1>Pablo Diego Ruiz y Picasso</F1>
<F2>Los Angeles</F2>
<F3>CA</F3>
</Row>
<Row>
<F1>Jane Doe</F1>
<F2>La Villa Real de la Santa Fe de San Francisco de Asis</F2>
<F3>NM</F3>
</Row>
</Data>
产生了想要的、正确的结果:
[Created By] [City] [Region]
____________________________ _______________________________________________________ ________
Pablo Diego Ruiz y Picasso Los Angeles CA
[Created By] [City] [Region]
____________________________ _______________________________________________________ ________
Jane Doe La Villa Real de la Santa Fe de San Francisco de Asis NM
IV.第 III 部分(上文)的 XSLT 1.0 翻译:
请注意:
如果有 100 行每行 4 列,JLRishe 提供的解决方案作为对他最初答案的更正将执行 400 次排序。
下面的代码没有这样低效的地方:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ext="http://exslt.org/common">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:variable name="vMaxCols">
<xsl:call-template name="maxChildren">
<xsl:with-param name="pNodes" select="/*/*"/>
</xsl:call-template>
</xsl:variable>
<xsl:variable name="vrtfMax">
<xsl:for-each select="(/*/*/*)[not(position() > $vMaxCols)]">
<xsl:variable name="vPos" select="position()"/>
<length>
<xsl:call-template name="maxLength">
<xsl:with-param name="pNodes" select="/*/*/*[position()=$vPos]"/>
</xsl:call-template>
</length>
</xsl:for-each>
</xsl:variable>
<xsl:variable name="vMax" select="ext:node-set($vrtfMax)/length"/>
<xsl:variable name="vrtfUnderscores">
<xsl:for-each select="(/*/*/*)[not(position() > $vMaxCols)]">
<xsl:variable name="vPos" select="position()"/>
<xsl:variable name="vLongestDataNode" select=
"/*/*/*[position()=$vPos
and string-length() = $vMax[position() = $vPos]][1]"/>
<t>
<xsl:value-of select=
"concat('__',
translate($vLongestDataNode,translate($vLongestDataNode, '_', ''),
'_________________________________________________________')
)"/>
</t>
</xsl:for-each>
</xsl:variable>
<xsl:variable name="vUnderscores" select="ext:node-set($vrtfUnderscores)/t"/>
<xsl:variable name="vrtfBlanks">
<xsl:for-each select="$vUnderscores">
<xsl:variable name="vPos" select="position()"/>
<t><xsl:value-of select=
"translate($vUnderscores[position()=$vPos],'_', ' ')"/>
</t>
</xsl:for-each>
</xsl:variable>
<xsl:variable name="vBlanks" select="ext:node-set($vrtfBlanks)/t"/>
<xsl:variable name="vrtfTitle">
<xsl:for-each select="/*/*[1]/*">
<xsl:variable name="vPos" select="position()"/>
<t>
<xsl:value-of select=
"concat('[',.,']',
substring($vBlanks[position()=$vPos],1,
2+$vMax[position()=$vPos]-string-length())
)
"/>
</t>
</xsl:for-each>
</xsl:variable>
<xsl:variable name="vTitle" select="ext:node-set($vrtfTitle)/t"/>
<xsl:template match="Row">
<xsl:text>
</xsl:text>
<xsl:for-each select="$vTitle">
<xsl:value-of select="."/>
</xsl:for-each>
<xsl:text>
</xsl:text>
<xsl:for-each select="$vUnderscores">
<xsl:value-of select="."/>
<xsl:text> </xsl:text>
</xsl:for-each>
<xsl:text>
</xsl:text>
<xsl:for-each select="*[not(position() > $vMaxCols)]">
<xsl:variable name="vPos" select="position()"/>
<xsl:value-of select=
"concat(.,
substring($vBlanks[position()=$vPos],
1,
string-length($vBlanks[position()=$vPos])
-string-length()),
' '
)"/>
</xsl:for-each>
<xsl:text>
</xsl:text>
</xsl:template>
<xsl:template name="maxChildren">
<xsl:param name="pNodes" select="/.."/>
<xsl:for-each select="$pNodes">
<xsl:sort select="count(*)"
data-type="number" order="descending"/>
<xsl:if test="position() = 1">
<xsl:value-of select="count(*)"/>
</xsl:if>
</xsl:for-each>
</xsl:template>
<xsl:template name="maxLength">
<xsl:param name="pNodes" select="/.."/>
<xsl:for-each select="$pNodes">
<xsl:sort select="string-length()"
data-type="number" order="descending"/>
<xsl:if test="position() = 1">
<xsl:value-of select="string-length()"/>
</xsl:if>
</xsl:for-each>
</xsl:template>
<xsl:template match="Row[1]|text()"/>
</xsl:stylesheet>
关于xml - 使用 XSL 重复 XML 文件中的第一个节点,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15451985/