jQuery XML解析如何获取元素属性

Question

XML:

<item>
     <title>Some title</title>

     <description>
     <![CDATA[
      Some description text Some description text Some description text Some description text Some description text Some description text 
      Some description text Some description text Some description text Some description text Some description text Some description text 
      Some description text Some description text Some description text Some description text Some description text Some description text 
      Some description text Some description text Some description text Some description text Some description text Some description text 
     ]]>
     </description>

     <media:content isDefault="true" medium="image" url="http://sampledomain.com/image.jpg">
      <media:title>Image title</media:title>
      <media:description>Image description</media:description>
      <media:thumbnail url="http://sampledomain.com/image.jpg" width="160" height="120" />
     </media:content>

     <wfw:commentRss>http://sampledomain.com/comment/feed/</wfw:commentRss>
     <slash:comments>0</slash:comments>
    </item>

我正在从 ajax 获取 css，在 onsuccess 函数中我的代码如下:

$(xml).find('item').each(function() {
 var title = $(this).find('title').eq(0).text();
 var url   = $(this).find('content').attr('url');

 // Printing url as undefined
 alert(url);
 console.log($(this).find('content');

});

我想要获取的内容 url 属性我正在获取项目子项(标题、描述、内容、commentRss 和评论) 但是当我尝试获取 $(this).find('content') 时，它没有给我任何东西 谁能弄清楚我做错了什么？ 谢谢

Answer 1

您的 XML 使用命名空间。

请参阅关于 namespace 的类似 Stack Overflow 问题。你必须避开冒号:

jQuery XML parsing with namespaces